Chapter 12: Problem 67
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}-4 y^{2}=1 $$
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Chapter 12: Problem 67
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}-4 y^{2}=1 $$
These are the key concepts you need to understand to accurately answer the question.
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Show that the volume of the segment cut from the paraboloid $$ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=\frac{z}{c} $$ by the plane \(z=h\) equals half the segment's base times its altitude. (Figure 12.49 shows the segment for the special case \(h=c . )\)
a. Express the area \(A\) of the cross-section cut from the ellipsoid $$ x^{2}+\frac{y^{2}}{4}+\frac{z^{2}}{9}=1 $$ by the plane \(z=c\) as a function of \(c .\) (The area of an ellipse with semiaxes \(a\) and \(b\) is \(\pi a b . )\) b. Use slices perpendicular to the \(z\) -axis to find the volume of the ellipsoid in part (a). c. Now find the volume of the ellipsoid $$ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1 $$ Does your formula give the volume of a sphere of radius \(a\) if \(a=b=c ?\)
Double cancellation If \(\mathbf{u} \neq \mathbf{0}\) and if \(\mathbf{u} \times \mathbf{v}=\mathbf{u} \times \mathbf{w}\) and \(\mathbf{u} \cdot \mathbf{v}=\mathbf{u} \cdot \mathbf{w},\) then does \(\mathbf{v}=\mathbf{w} ?\) Give reasons for your answer.
Sketch the surfaces in Exercises \(13-76\) $$ z=1+y^{2}-x^{2} $$
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}+4 z^{2}=16 $$
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