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Find the binomial series for the functions in Exercises \(11-14\) . $$ \left(1-\frac{x}{2}\right)^{4} $$

Short Answer

Expert verified
\((1 - \frac{x}{2})^4 = 1 - 2x + \frac{3x^2}{2} - \frac{x^3}{2} + \frac{x^4}{16}\)

Step by step solution

01

Understand the Binomial Series

The binomial series for the expansion of \((1 + u)^n\) is given by the formula:\[ (1 + u)^n = \sum_{k=0}^{\infty} \binom{n}{k} u^k \]where \(\binom{n}{k}\) is the binomial coefficient. In this problem, we have \(u = -\frac{x}{2}\) and \(n = 4\).
02

Apply the Binomial Formula

Substitute \(u = -\frac{x}{2}\) and \(n = 4\) into the binomial formula:\[(1 - \frac{x}{2})^4 = \sum_{k=0}^{4} \binom{4}{k} \left(-\frac{x}{2}\right)^k\]Note that the series stops at \(n = 4\) because the series will have only terms from 0 to 4 as the exponent is a positive integer.
03

Calculate Binomial Coefficients

Compute the binomial coefficients \(\binom{4}{k}\) for \(k = 0, 1, 2, 3, 4\):- \(\binom{4}{0} = 1\)- \(\binom{4}{1} = 4\)- \(\binom{4}{2} = 6\)- \(\binom{4}{3} = 4\)- \(\binom{4}{4} = 1\)
04

Calculate Each Term in the Series

Calculate each term of the series using \(\binom{4}{k}\) and \(\left(-\frac{x}{2}\right)^k\):- For \(k=0\): \(\binom{4}{0}\left(-\frac{x}{2}\right)^0 = 1\)- For \(k=1\): \(\binom{4}{1}\left(-\frac{x}{2}\right)^1 = 4\left(-\frac{x}{2}\right) = -2x\)- For \(k=2\): \(\binom{4}{2}\left(-\frac{x}{2}\right)^2 = 6\left(\frac{x^2}{4}\right) = \frac{3x^2}{2}\)- For \(k=3\): \(\binom{4}{3}\left(-\frac{x}{2}\right)^3 = 4\left(-\frac{x^3}{8}\right) = -\frac{x^3}{2}\)- For \(k=4\): \(\binom{4}{4}\left(-\frac{x}{2}\right)^4 = 1\left(\frac{x^4}{16}\right) = \frac{x^4}{16}\)
05

Write the Complete Binomial Series

Combine all calculated terms to get the binomial series:\[(1 - \frac{x}{2})^4 = 1 - 2x + \frac{3x^2}{2} - \frac{x^3}{2} + \frac{x^4}{16}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient is a fundamental element in the world of mathematics, particularly when dealing with polynomial expansions. It is represented as \(\binom{n}{k}\), and is defined to be the number of ways to choose \(k\) elements from a set of \(n\) elements without regard to order. That's why it's sometimes called a "combinatorial number."

The formula for calculating a binomial coefficient is given by:
  • \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\)
Here, \(n!\) ("n factorial") represents the product of all positive integers up to \(n\), and \(k!\) is the factorial of \(k\). Factorial expressions are used to manage permutations and combinations in the calculations.

For example, in our exercise, the binomial coefficients for \((1 - \frac{x}{2})^4\) were calculated as:
  • \(\binom{4}{0} = 1\)
  • \(\binom{4}{1} = 4\)
  • \(\binom{4}{2} = 6\)
  • \(\binom{4}{3} = 4\)
  • \(\binom{4}{4} = 1\)
The binomial coefficients serve as multipliers for each term in a polynomial expansion, helping us to construct the series terms systematically.
Polynomial Expansion
Polynomial expansion is a process in algebra where an expression like \((a + b)^n\) is expanded into a sum of terms. Each term is calculated by using powers of \(a\) and \(b\), multiplied by the binomial coefficients.

This technique allows us to transform a compact expression into a more detailed form, which is especially useful in calculus and series analysis.
  • Polynomial expansions provide deeper insights into the behavior of functions.
  • They are essential for approximations and are often used in numerical and applied mathematics.
For the function \((1 - \frac{x}{2})^4\) given in our exercise, the polynomial expansion process involves employing the binomial formula:
  • \(\sum_{k=0}^{4} \binom{4}{k} \left(-\frac{x}{2}\right)^k\)
By applying this, we generated terms like \(-2x\), \(\frac{3x^2}{2}\), \(-\frac{x^3}{2}\), and \(\frac{x^4}{16}\). This expansion converts the original expression into a sum of polynomial elements, each representing a specific degree of \(x\). Polynomial expansion serves as a bridge to deeper mathematical exploration and understanding.
Series Expansion
Series expansion is a powerful tool used to express functions as the sum of a sequence of terms. In many cases, as with the binomial series expansion, it involves expressing a function of a given form through an infinite or finite sum.

One common form is the Taylor or Maclaurin series when approximating functions locally. However, the binomial series specifically utilizes the binomial formula to represent powers of binomials in series form.
  • Series expansions offer approximations to complex functions.
  • They are crucial for computations in fields such as physics and engineering.
In the exercise, the expansion of \((1 - \frac{x}{2})^4\) results in a finite series due to the integer exponent. The steps toward constructing this finite series involved:
  • Calculating each term based on its binomial coefficient and associated power of \(-\frac{x}{2}\).
  • Summing the calculated terms: \(1 - 2x + \frac{3x^2}{2} - \frac{x^3}{2} + \frac{x^4}{16}\).
Even though this series is finite, the principles of series expansion remain essential for understanding infinite cases, like in calculus, where they are used for approximating functions over specified intervals. Series expansions can make complex mathematical concepts more accessible, providing a step-by-step approach to function analysis and evaluation.

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Most popular questions from this chapter

Use a CAS to perform the following steps for the sequences in Exercises \(129-140 .\) a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$ a_{n}=\left(1+\frac{0.5}{n}\right)^{n} $$

Uniqueness of least upper bounds Show that if \(M_{1}\) and \(M_{2}\) are least upper bounds for the sequence \(\left\\{a_{n}\right\\},\) then \(M_{1}=M_{2} .\) That is, a sequence cannot have two different least upper bounds.

Show that if \(\sum_{n=1}^{\infty} a_{n}\) and \(\sum_{n=1}^{\infty} b_{n}\) both converge absolutely, then so does $$ \begin{array}{ll}{\text { a. } \sum_{n=1}^{\infty}\left(a_{n}+b_{n}\right)} & {\text { b. } \sum_{n=1}^{\infty}\left(a_{n}-b_{n}\right)} \\ {\text { c. } \sum_{n=1}^{\infty} k a_{n} \quad(k \text { any number })}\end{array} $$

Logistic difference equation The recursive relation $$ a_{n+1}=r a_{n}\left(1-a_{n}\right) $$ is called the logistic difference equation, and when the initial value \(a_{0}\) is given the equation defines the logistic sequence \(\left\\{a_{n}\right\\} .\) Throughout this exercise we choose \(a_{0}\) in the interval \(03.57\) . Choose \(r=3.65\) and calculate and plot the first 300 terms of \(\left\\{a_{n}\right\\} .\) Observe how the terms wander around in an unpredictable, chaotic fashion. You cannot predict the value of \(a_{n+1}\) from previous values of the sequence. g. For \(r=3.65\) choose two starting values of \(a_{0}\) that are close together, say, \(a_{0}=0.3\) and \(a_{0}=0.301 .\) Calculate and plot the first 300 values of the sequences determined by each starting value. Compare the behaviors observed in your plots. How far out do you go before the corresponding terms of your two sequences appear to depart from each other? Repeat the exploration for \(r=3.75 .\) Can you see how the plots look different depending on your choice of \(a_{0} ?\) We say that the logistic sequence is sensitive to the initial condition a_{0} .

Which of the series converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series’ convergence or divergence.) $$ \sum_{n=1}^{\infty} \frac{8 \tan ^{-1} n}{1+n^{2}} $$

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