Chapter 10: Problem 51
Exercises \(49-52\) give equations for ellipses and tell how many units up or down and to the right or left each ellipse is to be shifted. Find an equation for the new ellipse, and find the new foci, vertices, and center. $$ \frac{x^{2}}{3}+\frac{y^{2}}{2}=1, \quad \text { right } 2, \text { up } 3 $$
Short Answer
Step by step solution
Analyze the Original Equation
Identify the Horizontal and Vertical Shift
Write the Equation for the Shifted Ellipse
Determine the New Center of the Ellipse
Calculate the Vertices of the Shifted Ellipse
Determine the New Foci of the Shifted Ellipse
List the New Foci
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conic Sections
Ellipse Transformation
Center of Ellipse
Foci and Vertices of Ellipse
- Vertices: The vertices are points on the ellipse where it is widest and tallest. For our initial ellipse, vertices are along both x and y directions from the center. After transformation, they are recalculated as \((2\pm\sqrt{3}, 3)\) and \((2, 3\pm\sqrt{2})\), indicating maximum points along the semi-minor and semi-major axes.
- Foci: The foci are two fixed points located along the major axis. They help define the ellipse's "shape." Their units are found through the formula \(c = \sqrt{|a^2 - b^2|}\). In our example, this calculated \(c\approx0.41\) is subtracted and added vertically from the center, resulting in new foci positions at approximately \((2, 2.59)\) and \((2, 3.41)\).