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a. Find Cartesian equations for the curves \(r=4 \sin \theta\) and \(r=\sqrt{3} \sec \theta\) b. Sketch the curves together and label their points of intersection in both Cartesian and polar coordinates.

Short Answer

Expert verified
Cartesian curves: circle at \((0, 2)\) with radius 2 and line \(x=\sqrt{3}\). Intersection at \((\sqrt{3},3)\) and \((\sqrt{3},1)\). In polar: \((2\sqrt{3},\frac{\pi}{3})\) and \((2,\frac{\pi}{6})\).

Step by step solution

01

Convert Polar Equation to Cartesian for r=4sinθ

The given polar equation is \(r = 4 \sin \theta\). To convert to Cartesian coordinates, we use the relations: \(x = r \cos \theta\) and \(y = r \sin \theta\). Since \(y = r \sin \theta\), we have \(y = 4 \sin \theta\), which gives \(y = \frac{4r}{r} = 4\). Therefore, \((r = 4 \sin \theta)\) converts to the Cartesian equation \(x^2 + y^2 = 4y\). Rearranging, we get \((x^2 + (y - 2)^2 = 4)\), representing a circle centered at \((0, 2)\) with radius 2.
02

Convert Polar Equation to Cartesian for r=√3secθ

The given polar equation is \(r = \sqrt{3} \sec \theta\). The reciprocal identity of secant is \( \sec \theta = \frac{1}{\cos \theta} \), so \(r \cos \theta = \sqrt{3}\). Since \(x = r \cos \theta\), this directly translates to \(x = \sqrt{3}\), which is a vertical line.
03

Determine Points of Intersection of the Curves

To find the points of intersection of the circle \(x^2 + (y - 2)^2 = 4\) and the line \(x = \sqrt{3}\), substitute \(x = \sqrt{3}\) into the circle equation: \( (\sqrt{3})^2 + (y - 2)^2 = 4\), which simplifies to \(3 + (y - 2)^2 = 4\). Solving this gives \( (y - 2)^2 = 1\), so \(y = 3\) or \(y = 1\). Therefore, the intersection points in Cartesian coordinates are \((\sqrt{3}, 3)\) and \((\sqrt{3}, 1)\).
04

Determine Polar Coordinates of Intersection Points

Convert the Cartesian intersection points \((\sqrt{3}, 3)\) and \((\sqrt{3}, 1)\) to polar coordinates. The polar conversion is \( r = \sqrt{x^2 + y^2} \) and \( \tan \theta = \frac{y}{x} \). For \((\sqrt{3}, 3)\), \( r = \sqrt{(\sqrt{3})^2 + 3^2} = \sqrt{12} = 2\sqrt{3} \) and \( \theta = \tan^{-1}(\frac{3}{\sqrt{3}}) = \tan^{-1}(\sqrt{3}) = \frac{\pi}{3} \). For \((\sqrt{3}, 1)\), \( r = \sqrt{(\sqrt{3})^2 + 1^2} = 2 \) and \( \theta = \tan^{-1}(\frac{1}{\sqrt{3}}) = \tan^{-1}(\frac{1}{\sqrt{3}}) = \frac{\pi}{6} \). Thus, the polar coordinates are \((2\sqrt{3}, \frac{\pi}{3})\) and \((2, \frac{\pi}{6})\).
05

Sketch the Curves and Label Intersections

Draw the circle centered at \((0, 2)\) with radius 2, and the vertical line \(x = \sqrt{3}\). Mark the intersection points \((\sqrt{3}, 3)\) and \((\sqrt{3}, 1)\) in the Cartesian plane. Label the points of intersection also in polar coordinates as \((2\sqrt{3}, \frac{\pi}{3})\) and \((2, \frac{\pi}{6})\) on the sketch.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian coordinates
The Cartesian coordinate system is a framework for describing every point in a plane using two numbers, known typically as \(x\) and \(y\). These coordinates individually represent the horizontal and vertical distances of a point from a fixed reference origin. In essence, the Cartesian system breaks down locations in a grid-like format, making it intuitive for visualizing points, lines, and shapes on paper or a digital screen.
If you imagine a graph with two perpendicular lines, the horizontal line is the \(x\)-axis and the vertical line is the \(y\)-axis. Any point on this plane is expressed as \((x, y)\), where \(x\) reflects the position along the horizontal axis and \(y\) marks the place along the vertical axis. This simplicity and straightforward representation are why the Cartesian system is widely used in geometry and applied mathematics.
  • The Cartesian equation for a circle is usually written in the form \(x^2 + y^2 = r^2\) where \(r\) is the radius.
  • For a vertical line in the Cartesian plane, the equation takes the form \((x = \text{constant})\), denoting a fixed position along the \(x\)-axis.
polar coordinates
Unlike the Cartesian system, polar coordinates describe points in a plane with a different approach using the concepts of radius and angle. Each point is represented as \((r, \theta)\), where \(r\) is the distance from the origin (or pole) and \(\theta\) is the angle formed with the positive \(x\)-axis, usually measured in radians. This system is particularly useful when dealing with scenarios involving circles, arcs, or spirals.
One of the key characteristics of the polar coordinates is its natural fit for describing circular or rotational motion, which aligns well with many practical engineering and physics applications.
  • The relation between Cartesian and polar coordinates is given by \(x = r \cos \theta\) and \(y = r \sin \theta\), allowing us to switch between these two systems seamlessly.
  • This conversion is particularly useful when solving problems that involve circular motion paths, such as the curves defined by equations \(r = 4 \sin \theta\) and \(r = \sqrt{3} \sec \theta\) in our example.
points of intersection
Points of intersection are locations where two curves or lines meet in a geometric plane. Finding these is essential for understanding interactions between different shapes or dynamic paths. In the given example, the circle of equation \(x^2 + (y-2)^2 = 4\) and the line \(x = \sqrt{3}\) intersect at two points, which is a classic scenario in geometry.
To determine intersection points, one substitutes a variable from one equation into another, solving for the remaining variable. This method unveils the exact points at which the two shapes cross each other.
  • In our case, the intersection points were resolved by placing \(x = \sqrt{3}\) into the circle's equation and solving for \(y\).
  • The calculated pairs of coordinates are \((\sqrt{3}, 3)\) and \((\sqrt{3}, 1)\) in the Cartesian plane.
Beyond these calculations, visualizing the intersection in both geometric and algebraic forms enhances understanding of how different equations describe the same physical crossing points.
converting equations
Converting equations between Cartesian and polar forms is a common mathematical operation, particularly when dealing with curves in different coordinate systems. This conversion plays a crucial role because each system has its advantages for specific shapes and motions.
The polar equation \(r = 4 \sin \theta\) was converted to a Cartesian form by applying the relationship \(y = r \sin \theta\), giving the final equation for a circle centered at \((0, 2)\) with radius 2 in the Cartesian plane.
Similarly, \(r = \sqrt{3} \sec \theta\) translates effortlessly to the straightforward vertical line \(x = \sqrt{3}\) in Cartesian coordinates before proceeding with further analysis, like finding intersections.
  • Knowing these conversions allows for smoother transitions between problem-solving in the two systems.
  • Geometric understanding becomes effortless when the algebraic form matches our visual expectations for each curve described.
The knack for converting equations is crucial in broadening your ability to tackle complex multiform problems in advanced mathematics.

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Most popular questions from this chapter

The hyperbola \(\left(x^{2} / 16\right)-\left(y^{2} / 9\right)=1\) is shifted 2 units to the right to generate the hyperbola $$\frac{(x-2)^{2}}{16}-\frac{y^{2}}{9}=1$$ a. Find the center, foci, vertices, and asymptotes of the new hyperbola. b. Plot the new center, foci, vertices, and asymptotes, and sketch in the hyperbola.

In Exercises \(65-68\) , find a polar equation for the given curve. In each case, sketch a typical curve. $$ x^{2}+y^{2}-2 a y=0 $$

Exercises \(29-36\) give the eccentricities of conic sections with one focus at the origin, along with the directrix corresponding to that focus. Find a polar equation for each conic section. $$ e=1 / 2, \quad x=1 $$

\(r=f(\boldsymbol{\theta})\) vs. \(\boldsymbol{r}=2 \boldsymbol{f}(\boldsymbol{\theta}) \quad\) The curves \(r=f(\theta), \alpha \leq \theta \leq \beta,\) and \(r=2 f(\theta), \alpha \leq \theta \leq \beta,\) are revolved about the \(x\) -axis to generate surfaces. Can anything be said about the relative areas of these surfaces? Give reasons for your answer.

Average value If \(f\) is continuous, the average value of the polar coordinate \(r\) over the curve \(r=f(\theta), \alpha \leq \theta \leq \beta,\) with respect to \(\theta\) is given by the formula $$r_{\text { av }}=\frac{1}{\beta-\alpha} \int_{\alpha}^{\beta} f(\theta) d \theta$$ Use this formula to find the average value of \(r\) with respect to \(\theta\) over the following curves \((a>0)\) a. The cardioid \(r=a(1-\cos \theta)\) b. The circle \(r=a\) c. The circle \(r=a \cos \theta, \quad-\pi / 2 \leq \theta \leq \pi / 2\)

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