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At a workshop on enhancing creativity, \(\frac{1}{4}\) of the participants are musicians, \(\frac{2}{5}\) are artists, \(\frac{1}{10}\) are actors, and the remaining participants are writers. What fraction of the people attending the workshop are writers?

Short Answer

Expert verified
Therefore, \( \frac{1}{4}\) of the people attending the workshop are writers.

Step by step solution

01

Identify the known fractions

Firstly, note down the known fractions. Musicians make up \(\frac{1}{4}\) of the workshop, artists make up \(\frac{2}{5}\), and actors make up \(\frac{1}{10}\).
02

Add the known fractions together

Add those fractions together. \(\frac{1}{4} + \(\frac{2}{5} + \(\frac{1}{10} = \(\frac{47}{100}\). It might be easier to convert all fractions to have the lowest common denominator (in this case 100), so \( \frac{1}{4}\) becomes \( \frac{25}{100}\), \( \frac{2}{5}\) becomes \( \frac{40}{100}\) and \( \frac{1}{10}\) remains \( \frac{10}{100}\). The sum is then calculated as \( \frac{25+40+10}{100} = \frac{75}{100} = \frac{3}{4}\).
03

Deduct the sum of known fractions from 1

Deduct the combined fraction \( \frac{3}{4}\) of the musicians, artists, and actors from 1. This can also be seen as \( \frac{4}{4}\) – \( \frac{3}{4}\) = \( \frac{1}{4}\). So, \( \frac{1}{4}\) of the participants in the workshop are writers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Adding Fractions
Adding fractions can be quite simple when you follow the right steps. To begin, you must ensure that all fractions involved have a common denominator. The denominator is the bottom number of a fraction and it represents the total number of equal parts something is divided into. If the denominators are the same, you can add the numerators directly. The numerator is the top number of the fraction, showing how many parts are being considered. For instance, if you have fractions with a common denominator like \( \frac{1}{4} \) and \( \frac{2}{4} \), you just add the numerators to get \( \frac{3}{4} \). When the fractions don't have the same denominator, convert them to equivalent fractions with the same denominator before adding them.
Common Denominator
Finding a common denominator is a crucial step in both adding and subtracting fractions. A common denominator is a shared multiple of the denominators of the fractions you're working with.
  • Identify the least common multiple (LCM) of the denominators.
  • Adjust each fraction so that they all have this common denominator.
For example, with fractions like \( \frac{1}{4} \), \( \frac{2}{5} \), and \( \frac{1}{10} \), the LCM of 4, 5, and 10 is 20. Hence, convert each fraction:
  • \( \frac{1}{4} \) becomes \( \frac{5}{20} \)
  • \( \frac{2}{5} \) becomes \( \frac{8}{20} \)
  • \( \frac{1}{10} \) becomes \( \frac{2}{20} \)
Now that they have a common denominator, you can add them easily.
Fraction Subtraction
When it comes to subtracting fractions, the process is somewhat similar to adding fractions. You need to ensure that the fractions have the same denominator first.Once they do, subtract the numerators and keep the denominator unchanged. For example, to find out what fraction of the workshop participants are writers in the given exercise:
  • Firstly, find the sum of the known fractions of musicians, artists, and actors.
  • The combined fraction \( \frac{3}{4} \) is subtracted from 1, since 1 represents the whole.
  • Expressing 1 as \( \frac{4}{4} \), subtract \( \frac{3}{4} \) to get \( \frac{1}{4} \). This represents the writers.
Subtraction essentially removes parts, so remember to first adjust the fractions to a common denominator before carrying out the subtraction.
Fractions in Real Life
Fractions are not just a mathematical concept but a part of our daily lives. They represent how we divide things into parts and can express quantities that are less than a whole. Let's look at some real-life examples:
  • Cooking: Recipes often call for fractions of cups, teaspoons, or tablespoons. For instance, adding \( \frac{1}{2} \) cup of flour and \( \frac{1}{4} \) cup of sugar.
  • Time Management: We often talk about time in fractions, such as half an hour (\( \frac{1}{2} \) hour) or a quarter past the hour (\( \frac{1}{4} \) hour).
  • Shopping and Dividing Costs: Splitting a pizza into slices, dividing bills, or even understanding discounts and sales involve fractions.
Understanding fractions and how to work with them using addition, subtraction, and finding common denominators can make daily tasks easier. Once you grasp these concepts, you'll see just how frequently fractions pop up in everyday life.

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Most popular questions from this chapter

The sum, \(S_{n}\), of the first \(n\) terms of an arithmetic sequence is given by$$S_{n}=\frac{n}{2}\left(a_{1}+a_{n}\right),$$in which \(a_{1}\) is the first term and \(a_{n}\) is the nth term. The sum, \(S_{n}\), of the first \(n\) terms of a geometric sequence is given by$$S_{n}=\frac{a_{1}\left(1-r^{n}\right)}{1-r},$$in which \(a_{1}\) is the first term and \(r\) is the common ratio \((r \neq 1)\). Determine whether each sequence is arithmetic or geometric. Then use the appropriate formula to find \(S_{10}\), the sum of the first ten terms. \(4,-12,36,-108, \ldots\)

Write the first six terms of the geometric sequence with the first term, \(a_{1}\), and common ratio, \(r\). \(a_{1}=3000, r=-1\)

Find the indicated term for the geometric sequence with first term, \(a_{1}\), and common ratio, \(r\). Find \(a_{8}\), when \(a_{1}=1,000,000, r=0.1\).

Suppose you save \$1 the first day of a month, \(\$ 2\) the second day, \(\$ 4\) the third day, and so on. That is, each day you save twice as much as you did the day before. What will you put aside for savings on the thirtieth day of the month?

In Exercises 133-134, you will develop geometric sequences that model the population growth for California and Texas, the two most populated U.S. states. The table shows the population of California for 2000 and 2010 , with estimates given by the U.S. Census Bureau for 2001 through \(2009 .\) $$ \begin{aligned} &\begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & \mathbf{2 0 0 0} & \mathbf{2 0 0 1} & \mathbf{2 0 0 2} & \mathbf{2 0 0 3} & \mathbf{2 0 0 4} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 33.87 & 34.21 & 34.55 & 34.90 & 35.25 \\ \hline \end{array}\\\ &\begin{array}{|l|c|c|c|c|c|c|} \hline \text { Year } & \mathbf{2 0 0 5} & \mathbf{2 0 0 6} & \mathbf{2 0 0 7} & \mathbf{2 0 0 8} & \mathbf{2 0 0 9} & \mathbf{2 0 1 0} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 35.60 & 36.00 & 36.36 & 36.72 & 37.09 & 37.25 \\ \hline \end{array} \end{aligned} $$ a. Divide the population for each year by the population in the preceding year. Round to two decimal places and show that California has a population increase that is approximately geometric. b. Write the general term of the geometric sequence modeling California's population, in millions, \(n\) years after \(1999 .\) c. Use your model from part (b) to project California's population, in millions, for the year 2020 . Round to two decimal places.

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