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Write the first six terms of the geometric sequence with the first term, \(a_{1}\), and common ratio, \(r\). \(a_{1}=3000, r=-1\)

Short Answer

Expert verified
The first six terms of the geometric sequence are: 3000, -3000, 3000, -3000, 3000, -3000.

Step by step solution

01

Identify the values of \(a_{1}\) and \(r\)

From the exercise, the first term (\(a_{1}\)) given is 3000 and the common ratio (\(r\)) is -1.
02

Find the first six terms

As the first term (\(a_{1}\)) is known, the formula will be applied from the 2nd term onwards. By substituting \(a_{1}\) and \(r\) into the formula \(a_n = a_{1}.r^{(n-1)}\), we can find the first six terms. The first term is \(a_{1} = 3000\). For the 2nd term, \(n=2\), substitute into the formula:\(a_{2} = a_{1}.r^{(2-1)} = 3000 \times -1 = -3000\)For the 3rd term, \(n=3\), substitute into the formula:\(a_{3} = a_{1}.r^{(3-1)} = 3000 \times -1^{(3-1)} = 3000\)Follow the same process for \(n=4\), \(n=5\) and \(n=6\).
03

Verification

The calculated results show a pattern where the terms alternate between negative and positive, and the absolute value is 3000 in each case. This is expected because the common ratio is -1, which changes the sign of each term in the sequence. Therefore, the generated sequence is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ratio
Understanding the common ratio is crucial when dealing with geometric sequences. The common ratio, denoted as \( r \), is a constant that each term of the sequence is multiplied by to obtain the subsequent term. To visualize this concept, imagine a chain where each link is created by multiplying the previous link by the common ratio.

In the provided example, \( r = -1 \). This means that every term in the sequence is multiplied by -1 to produce the next term. As a result, every term alternates in sign. If \( r \) were a positive number, each term would be either consistently increasing or decreasing depending on whether \( r \) is greater than or less than 1, respectively. With \( r \) being negative, it's quite fascinating to witness the alternating signs, like flipping a coin from heads to tails with each consecutive flip.

For comprehension, let's illustrate this with a simplistic example:
  • If the first term is 5 and the common ratio is 2, then the sequence would be 5, 10, 20, 40, and so on.
  • If we introduce a negative common ratio, say -2, beginning with 5, the sequence turns into 5, -10, 20, -40, continuing to alternate in sign.
This alternating pattern adds an interesting dynamic to the behavior of geometric sequences.
Sequence Terms Calculation
Calculating individual terms of a geometric sequence involves an understanding of the sequence's formula and the ability to apply it to find specific terms. The generic formula for finding the \( n^{th} \) term of a geometric sequence is \( a_n = a_{1} \times r^{(n-1)} \), where \( a_n \) is the term to find, \( a_{1} \) is the first term, and \( n \) is the term number.

In our exercise, the first term is 3000, and since the common ratio \( r \) is -1, we apply the calculation for the second term by raising the common ratio to the power of \( n-1 = 2-1 = 1 \), giving us \( a_{2} = a_{1} \times r^{(2-1)} = 3000 \times -1 = -3000 \). This process continues for all subsequent terms, staying aware that the exponent will dictate whether the term will be positive or negative due to the nature of the common ratio being -1.

By using this formula, students can calculate any term in a geometric sequence, not just the first six terms. This is a powerful tool, as it allows for a deep understanding and ability to navigate within the sequence without having to write down each term.
Arithmetic Operations in Sequences
Arithmetic operations in sequences such as geometric sequences allow you to manipulate and analyze the sequences further. These operations, including addition, subtraction, multiplication, and division, can be applied to the terms of the sequence. But in the context of a geometric sequence, multiplication and division are the key players since they directly relate to the common ratio.

For instance, finding the sum of a geometric sequence involves multiplying terms, while finding the common ratio often involves dividing successive terms. In the example given, if we were to find the sum of the first six terms, we would add them together, keeping in mind their alternating signs, to reach the sum. On the other hand, dividing any term by its preceding term (except the first since there is no term before it) in this sequence would consistently give us the common ratio \( r = -1 \).

These arithmetic operations enable us to explore properties such as the behavior of the sequence over time, the sum of a certain number of terms (geometric series), and the overall nature of the sequence's progression. The mastery of these operations reveals a deeper level of understanding and unlocks the potential for advanced topics like infinite series and convergence.

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Most popular questions from this chapter

Write the first six terms of the geometric sequence with the first term, \(a_{1}\), and common ratio, \(r\). \(a_{1}=1000, r=1\)

In Exercises 71-90, find the indicated term for the geometric sequence with first term, \(a_{1}\), and common ratio, \(r\). Find \(a_{7}\), when \(a_{1}=4, r=2\).

Find the indicated term for the geometric sequence with first term, \(a_{1}\), and common ratio, \(r\). Find \(a_{5}\), when \(a_{1}=4, r=3\).

In Exercises 133-134, you will develop geometric sequences that model the population growth for California and Texas, the two most populated U.S. states. The table shows the population of California for 2000 and 2010 , with estimates given by the U.S. Census Bureau for 2001 through \(2009 .\) $$ \begin{aligned} &\begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & \mathbf{2 0 0 0} & \mathbf{2 0 0 1} & \mathbf{2 0 0 2} & \mathbf{2 0 0 3} & \mathbf{2 0 0 4} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 33.87 & 34.21 & 34.55 & 34.90 & 35.25 \\ \hline \end{array}\\\ &\begin{array}{|l|c|c|c|c|c|c|} \hline \text { Year } & \mathbf{2 0 0 5} & \mathbf{2 0 0 6} & \mathbf{2 0 0 7} & \mathbf{2 0 0 8} & \mathbf{2 0 0 9} & \mathbf{2 0 1 0} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 35.60 & 36.00 & 36.36 & 36.72 & 37.09 & 37.25 \\ \hline \end{array} \end{aligned} $$ a. Divide the population for each year by the population in the preceding year. Round to two decimal places and show that California has a population increase that is approximately geometric. b. Write the general term of the geometric sequence modeling California's population, in millions, \(n\) years after \(1999 .\) c. Use your model from part (b) to project California's population, in millions, for the year 2020 . Round to two decimal places.

Determine whether each sequence is arithmetic or geometric. Then find the next two terms. \(5,15,45,135, \ldots\)

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