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A researcher claims to have found a drug that causes people to grow taller. The coach of the basketball team at Brandon University has expressed interest but demands evidence. Over 1000 Brandon students volunteer to participate in an experiment to test this new drug. Fifty of the volunteers are randomly selected, their heights are measured, and they are given the drug. Two weeks later, their heights are measured again. The power of the test to detect an average increase in height of 1 inch could be increased by

a. using only volunteers from the basketball team in the experiment.

b. using=0.05 instead of =0.05

c. using =0.05instead of =0.01

d. giving the drug to 25 randomly selected students instead of 50.

e. using a two-sided test instead of a one-sided test.

Short Answer

Expert verified

Using=0.05instead of=0.01

Step by step solution

01

Step 1:Given information

A researcher claims to have found a drug that causes people to grow taller. The coach of the basketball team at Brandon University has expressed interest but demands evidence. Over 1000 Brandon students volunteer to participate in an experiment to test this new drug. Fifty of the volunteers are randomly selected, their heights are measured, and they are given the drug. Two weeks later, their heights are measured again

02

Step 2:Explaination

You can increase the power by:

Increasing the sample size because having more information about the population will allow us to make better estimations

Increasing the significance level because this increases the probability of making a Type I error and decreases the probability of making a Type II error:

Making the alternative proportion por mean more extreme

Hence, the correct option is (c)

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Most popular questions from this chapter

Two-sided test Suppose you want to perform a test of H0:=64

versus Ha:notequalto64at the =0.05significance level. A random sample

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(a)z=0.64-0.50.64(0.36)100z=0.64-0.50.64(0.36)100

role="math" localid="1654432946823" (b)t=0.64-0.50.64(0.36)100t=0.64-0.50.64(0.36)100

(c)z=0.64-0.50.5(0.5)100z=0.64-0.50.5(0.5)100

(d)z=0.64-0.50.64(0.36)64z=0.64-0.50.64(0.36)64

(e)z=0.5-0.640.5(0.5)100z=0.5-0.640.5(0.5)100

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