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Suppose that the sample proportion of students who did all their assigned homework last week is p^=57100=0.57. Would this sample proportion provide convincing evidence that less than 60%of all students at the school completed all their assigned homework last week? Explain your reasoning.

Short Answer

Expert verified

A sample proportion of p^≤0.57happened 78250=31.27%of the time, so it would not be surprising to get p^≤0.57. Since it is not surprising, it does not provide convincing evidence.

Step by step solution

01

Given information

We have been given that the sample proportion of students who did all their assigned homework last week is p^=57100=0.57

02

Explanation

The sample proportion (p^) refers to the percentage of people in a sample who have a particular attribute or trait. The sample proportion is the percentage of successful samples; to calculate it, divide the number of people (or objects) who have the desired feature by the total number of persons (or items) in the sample.

Because 78250=31.27%, of the values of p^in the simulation are less than or equal to 0.57, a sample fraction of p^=0.57or less in an SRS of size 100from a population with p =0.60 would not be surprising. A sample proportion of p^≤0.57does not provide convincing evidence that the population proportion of students who completed all of their assigned homework is less than p^=60%.

The disparity between the observed proportion (p^=0.57) and the proportion stated (p =0.60) could be explained by sampling variability.

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Most popular questions from this chapter

A 10-question multiple-choice exam offers 5 choices for each question. Jason just guesses the answers, so he has probability 15of getting any one answer correct. You want to perform a simulation to determine the number of correct answers that Jason gets. What would be a proper way to use a table of random digits to do this?

a. One digit from the random digit table simulates one answer, with 5 = correct and all other digits = incorrect. Ten digits from the table simulate 10 answers.

b. One digit from the random digit table simulates one answer, with 0 or 1 = correct and all other digits = incorrect. Ten digits from the table simulate 10 answers.

c. One digit from the random digit table simulates one answer, with odd = correct and even = incorrect. Ten digits from the table simulate 10 answers.

d. One digit from the random digit table simulates one answer, with 0 or 1 = correct and all other digits = incorrect, ignoring repeats. Ten digits from the table simulate 10 answers.

e. Two digits from the random digit table simulate one answer, with 00 to 20 = correct and 21 to 99 = incorrect. Ten pairs of digits from the table simulate 10 answers.

Sample medians List all 10possible SRSs of size n=3, calculate the median quiz score for each sample, and display the sampling distribution of the sample median on a dotplot.

Sample proportions List all 10possible SRSs of size n=2, calculate the proportion of females for each sample, and display the sampling distribution of the sample proportion on a dotplot.

A researcher initially plans to take an SRS of size 160 from a certain population and calculate the sample mean x-x¯. Later, the researcher decides to increase the sample size so that the standard deviation of the sampling distribution of x-x¯will be half as big as when using a sample size of 160 . What sample size should the researcher use?

a. 40

b. 80

c. 320

d. 640

e. There is not enough information to determine the sample size.

The student newspaper at a large university asks an SRS of 250 undergraduates, "Do you favor eliminating the carnival from the term-end celebration?" All in all, 150 of the 250 are in favor. Suppose that (unknown to you) 55\% of all undergraduates favor eliminating the carnival. If you took a very large number of SRSs of size n=250 n=250 from this population, the sampling distribution of the sample proportion p∧p^would be

a. exactly Normal with mean 0.55 and standard deviation 0.03.

b. approximately Normal with mean 0.55 and standard deviation 0.03.

c. exactly Normal with mean 0.60 and standard deviation 0.03.

d. approximately Normal with mean 0.60 and standard deviation 0.03.

e. heavily skewed with mean 0.55 and standard deviation 0.03.

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