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The likelihood that a randomly selected subject completes more tasks than expected in a 5-minute period while listening to relaxing music.

Consider that the distribution of probability is

The number of puzzles predicted to be completed in a 5-minute period while listening to smoothing music can be calculated as follows:

$$\begin{gathered} E\left(x\right)=鈭�xp\left(x\right) \\ =1(0.2)+2(0.4)+3(0.3)+4(0.1) \\ =0.2+0.8+0.9+0.4 \\ =2.3 \end{gathered}$$

Thus, the likelihood that a randomly selected subject completes more problems than expected in a 5-minute period while listening to calming music can be computed as follows:

(a) The resultant probability will not be 0.1

(b) The resultant probability will not be 0.4

(c) The resultant probability will not be 0.8

(d) The resultant probability not be 1