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During the winter months, the temperatures at the Starneses鈥 Colorado cabin can stay well below freezing (32For0C)for weeks at a time. To prevent the pipes from freezing, Mrs. Starnes sets the thermostat at 50F.She also buys a digital thermometer that records the indoor temperature each night at midnight. Unfortunately, the thermometer is programmed to measure the temperature in degrees Celsius. Based on several years鈥 worth of data, the temperature Tin the cabin at midnight on a randomly selected night can be modeled by a Normal distribution with mean 8.5Cand standard deviation 2.25C. Let Y=the temperature in the cabin at midnight on a randomly selected night in degrees Fahrenheit (recall thatF=(9/5)C+32).

a. Find the mean of Y.

b. Calculate and interpret the standard deviation of Y.

c. Find the probability that the midnight temperature in the cabin is less than 40F.

Short Answer

Expert verified

a. The mean is47.3F.

b. The cabin's temperature at midnight on a randomly selected night fluctuates on average by 4.05F.

c. The probability that the cabin temperature at midnight is less than 40Fis 0.0359.

Step by step solution

01

Part(a) Step 1 : Given Information

Given :

Mrs. Starnes sets the thermostat at : 50掳F.

The temperature is modeled by a Normal distribution with mean: 8.5掳C Standard deviation : 2.25掳C.

Y = the temperature in the cabin at midnight

02

Part(a) Step 2 : Simplification 

We are aware that the degrees in Fahrenheit are calculated by multiplying the degrees in Celsius by Y(F)=95T(C)+32.

Then it was increased by the same amount.

The same constant constant 32is multiplied by every data value in the Tdistribution.

When the same constant is applied to each data value, the center of the distribution is also enlarged by the same constant.

Furthermore, if every data value is multiplied by the same constant, the distribution's center is multiplied by the same constant.

The mean is the center's measurement, as we all know.

As a result, the mean is :

Y=95T+32=95(8.5)+32=15.3+32=47.3F

03

Part(b) Step 1 : Given Information

Given :

Mrs. Starnes sets the thermostat at : 50F.

The temperature is modeled by a Normal distribution with mean: 8.5C Standard deviation : 2.25C.

Y=the temperature in the cabin at midnight

04

Part(b) Step 2 : Simplification 

We know, Y(F)=95T(C)+32

Then, in the Tdistribution, every data value is multiplied by the same constant 32and raised by the same constant.

The spread of the distribution is unaltered if every data value is multiplied by the same constant.

Furthermore, if every data value is multiplied by the same constant, the distribution's spread is also multiplied by the same constant.

The standard deviation is a measure of the spread, as we all know.

Thus, the standard deviation is :

Y=95T=95(2.25)=4.05F

05

Part(c) Step 1 : Given Information

Given :

Mrs. Starnes sets the thermostat at : 50F.

The temperature is modeled by a Normal distribution with mean: 8.5C Standard deviation : 2.25C.

Y=the temperature in the cabin at midnight

06

Part(c) Step 2 : Simplification 

Calculate the z-score using the formula :

z=x-=40-47.34.05=-1.80

To find the equivalent probability, use the normal probability table in the appendix.

For P(z<-1.80),look at the row that starts with -1.8and the column that starts with .00of the ordinary normal probability table.

P(x<40)=P(z<-1.80)=0.0359

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