91Ó°ÊÓ

Given table :

Since there are $4$crews on each flight, so :

$X=Y+4$

So, the new table is :

And so, the respective graph is :

The distribution is symmetric.

Given table :

$Y$stands for the number of passengers.

Each flight has four crew members, hence $X=Y+4$.

When the constant is added to each data value, the distribution's center is also enhanced by that constant value.

$$\begin{gathered} {\mathrm{μ}}_x={\mathrm{μ}}_y+4 \\ =37.4+5 \\ =\mathbf{41}\mathbf{.}\mathbf{4} \end{gathered}$$

When the constant value is added to each data point, the center of the distribution is raised, resulting in $41.4$average numbers of persons (passengers + staff) being randomly selected.

Given table :

$Y$stands for the number of passengers.

Because each flight has four crew members, adding the constant to each data value has no effect on the distribution's spread; it remains intact.

$1.24={\mathrm{σ}}_x={\mathrm{σ}}_y$

When a constant value is added to each data point, the spread of the distribution is unaffected, and the number of persons (passengers + staff) for a randomly chosen aircraft varies on average $1.24$around the mean = $41.4$people.