/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q .76. Rolling dice Suppose you roll tw... [FREE SOLUTION] | 91影视

91影视

Rolling dice Suppose you roll two fair, six-sided dice鈥攐ne red and one green. Are the events 鈥渟um is 8鈥 and 鈥済reen die shows a 4鈥 independent? Justify your answer. (See Figure 5.2 on page 314 for the sample space of this chance process.)

Short Answer

Expert verified

No, events "sum is 8 " and "green die shows a 4 " are not independent.

Step by step solution

01

Step 1:Given information

Two fair, six sided dice are rolled-one red and one green.

Two events:

"sum is 8"

And

"green die shows a 4"

02

Step 2:Calculation

Two events are independent, if the probability of occurrence of one event does not affect the probability of occurrence of other event.

Let

S8: sum is 8

G4: green die shows a 44

We know that

Green die shows a4

That means

For the sum to be 8, red needs to show a 4.

In this case, the number of favorable outcomes is 1and number of possible outcomes is6

The probability is calculated by dividing the number of favourable outcomes by the total number of possible possibilities.

P(S8G4)=Number of favorable outcomesNumber of possible outcomes=160.1667

Now,

The possible combinations to make 8:

(2,6),(3,5),(4,4),(5,3),(6,2)

In this case, since there are five possible combinations to make 8 .

Thus,

The number of favorable outcomes is 5and number of possible outcomes is 36

P(S8)=5360.1368

We have

P(S8G4)0.1368

And

P(S8)0.1667

Both probabilities are not identical.

Thus,

They are not independent.

.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You read in a book about bridge that the probability that each of the four players is dealt exactly one ace is approximately 0.11. This means that

a. in every 100bridge deals, each player has 1ace exactly 11times.

b. in 1million bridge deals, the number of deals on which each player has 1ace will be exactly 110,000.

c. in a very large number of bridge deals, the percent of deals on which each player has 1ace will be very close to 11%.

d. in a very large number of bridge deals, the average number of aces in a hand will be very close to 0.11.

e. If each player gets an ace in only 2of the first 50deals, then each player should get an ace in more than 11%of the next 50deals.

Crawl before you walk (At what age do babies learn to crawl? Does it take

longer to learn in the winter, when babies are often bundled in clothes that restrict their

movement? Perhaps there might even be an association between babies鈥 crawling age and

the average temperature during the month they first try to crawl (around 6months after

birth). Data were collected from parents who brought their babies to the University of

Denver Infant Study Center to participate in one of a number of studies. Parents reported

the birth month and the age at which their child was first able to creep or crawl a distance

of 4feet within one minute. Information was obtained on 414infants208boysand206girls. Crawling age is given in weeks, and average temperature (in degrees Fahrenheit) is

given for the month that is 6months after the birth month.

a. Make an appropriate graph to display the relationship between average temperature and

average crawling age. Describe what you see.

Some computer output from a least-squares regression analysis of the data is shown.

b. What is the equation of the least-squares regression line that describes the relationship

between average temperature and average crawling age? Define any variables that you

use.

c. Interpret the slope of the regression line.

d. Can we conclude that warmer temperatures 6months after babies are born causes them

to crawl sooner? Justify your answer.

Color-blind men About 7% of men in the United States have some form of red-green color blindness. Suppose we randomly select one U.S. adult male at a time until we find one who is red-green color-blind. Should we be surprised if it takes us 20 or more men? Describe how you would carry out a simulation to estimate the probability that we would have to randomly select 20 or more U.S. adult males to find one who is red-green color blind. Do not perform the simulation.

Cell phonesThe Pew Research Center asked a random sample of 2024adult cell-phone owners from the United States their age and which type of cell phone they own: iPhone, Android, or other (including non-smartphones). The two-way table summarizes the data.

Suppose we select one of the survey respondents at random. What鈥檚 the probability that:

a. The person is not age 18to 34and does not own an iPhone?

b. The person is age 18to 34or owns an iPhone?

What kind of vehicle? : Randomly select a new vehicle sold in the United States in a certain month. The probability distribution for the type of vehicle chosen is given here.

Vehicle TypePassenger carPickup TruckSUVCrossoverMinivan
Probability0.46
0.15
0.10
?
0.05

a. What is the probability that the vehicle is a crossover? How do you know?

b. Find the probability that vehicle is not an SUV or Minivan .

c. Given that the vehicle is not a passenger car, what is the probability that it is a pickup truck?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.