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Middle school values Researchers carried out a survey of fourth-, fifth-, and sixth-grade students in Michigan. Students were asked whether good grades, athletic ability, or being popular was most important to them. The two-way table summarizes the survey data.

Suppose we select one of these students at random. What鈥檚 the probability of each of the following?

a. The student is a sixth-grader or rated good grades as important.

b. The student is not a sixth-grader and did not rate good grades as important.

Short Answer

Expert verified

a. The probability that the student is a sixth 鈭 grader or rated good grades as important is0.6985

b. The probability that the student is not a sixth 鈭 grader and did no rate good grades as important is 0.3015

Step by step solution

01

Part (a) Step 1 : Given Information

We have to determine the probability that the student is a sixth 鈭 grader or rated good grades as important.

02

Part (a) Step 2 : Simplification

Take a look at the table's bottom right corner.
In total, 335students are enrolled.
Thus,
There are 335different outcomes to choose from.
Also,
For students who have received good grades or are in the sixth grade,
We'll obtain 234total if we add all the values in column "Grades" and row "6thgrade."
Thus,
There are a total of 234positive outcomes.
Now,
The probability is calculated by dividing the number of favourable outcomes by the total number of possible possibilities.

P(6thgradeorGrades)=NumberoffavourableoutcomesNumberofpossibleoutcomes=2343350.6985

03

Part (b) Step 1 : Given Information

We have to determine the probability that the student is not a sixth 鈭 grader and did no rate good grades as important.

04

Part (b) Step 2 : Simplification

Take a look at the table's bottom right corner.
In total, 335students are enrolled.
Thus,
There are 335different outcomes to choose from.
Also,
For the pupil who did not have good grades and was not in sixth grade,
We'll get 101if we add all the values from the 4thand 5thgrades in the columns "Athletic" and "Popular."
Thus,
The total number of positive outcomes is 101.
Now,
The probability is calculated by dividing the number of favourable outcomes by the total number of possible possibilities.

P(Not6thgraderandnoGrades)=NumberoffavourableoutcomesNumberofpossibleoutcomes=1013350.3015

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