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We need find what must be the probability that the customer is a college graduate who is not currently employed.

By using complement rule,

$\mathrm{P}\left({\mathrm{A}}^{\mathrm{c}}\right)=\mathrm{P}\left(\overline{\mathrm{A}}\right)=1-\mathrm{P}\left(\mathrm{A}\right)$

Undergraduate Student in business are $20\%$

Undergraduate Student in other fields are $15\%$

Graduates who are currently employed are $60\%$

Let,

P(Graduates who are currently employed ) is P(A)

Therefore,

$$\begin{gathered} \mathrm{P}\left({\mathrm{A}}^{\mathrm{c}}\right)=1-\mathrm{P}\left(\mathrm{A}\right) \\ =1-0.60 \\ =0.40 \end{gathered}$$

Hence, $0.40$must be the probability that the customer is a college graduate who is not currently employed

We need to find probability that the customer is currently an undergraduate.

By using addition rule of mutually exclusive events :

$\mathrm{P}(\mathrm{A}\mathrm{U}\mathrm{B})=\mathrm{P}(\mathrm{A}\mathrm{or}\mathrm{B})=\mathrm{P}\left(\mathrm{A}\right)+\mathrm{P}\left(\mathrm{B}\right)$

Undergraduate Student in business are $20\%$

Undergraduate Student in other fields are$15\%$

Graduates who are currently employed are $60\%$

Let,

P(Undergraduate Student in business ) is P(A)

P(Undergraduate Student in other fields ) is P(B)

Therefore

P(currently an undergraduate ) is

$$\begin{gathered} \mathrm{P}(\mathrm{A}\mathrm{U}\mathrm{B})=\mathrm{P}\left(\mathrm{A}\right)+\mathrm{P}\left(\mathrm{B}\right) \\ =0.20+0.15 \\ =0.35 \end{gathered}$$

Hence, probability that the customer is currently an undergraduate is $0.35$

We need to find the probability that the customer is not an undergraduate business student.

By using complement rule,

$\mathrm{P}\left({\mathrm{A}}^{\mathrm{c}}\right)=\mathrm{P}\left(\overline{\mathrm{A}}\right)=1-\mathrm{P}\left(\mathrm{A}\right)$

Undergraduate Student in business are $20\%$

Undergraduate Student in other fields are $15\%$

Graduates who are currently employed are $60\%$

Let.

P(undergraduate business student ) is P(B)

So, P(not an undergraduate business student) is

$\mathrm{P}\left(\overline{\mathrm{B}}\right)=1-\mathrm{P}\left(\mathrm{B}\right)=1-0.20=0.80$

Hence the probability that the customer is not an undergraduate business student is $0.80$