91影视

We are given a table. We need to explain validity of probability model.

As we know sum of all probabilities must be $1$and probabilities should lie between $0$and $1$

Sum of probabilities is $0.63+0.22+0.06+0.09=1$

Now, from the table we can say it follows both above mentioned conditions.

So, We can say the probability model is valid.

We are given a table. We need to find the probability that the chosen person鈥檚 mother tongue is not English.

Using complement rule, $\mathrm{P}\left({\mathrm{A}}^{\mathrm{c}}\right)=\mathrm{P}\left(\overline{\mathrm{A}}\right)=1-\mathrm{P}\left(\mathrm{A}\right)$

Probability of English : $\mathrm{P}\left(\mathrm{E}\right)=0.63$

Applying complement rule,

$\mathrm{P}\left({\mathrm{E}}^{\mathrm{c}}\right)=1-\mathrm{P}\left(\mathrm{E}\right)=1-0.63=0.37$

Hence, $0.37$ is the probability that the chosen person鈥檚 mother tongue is not English.

We are given a table. We need to find the probability that the chosen person鈥檚 mother tongue is one of Canada鈥檚 official languages.

Using addition rule of mutually exclusive for disjoint events,

$\mathrm{P}(\mathrm{A}\mathrm{U}\mathrm{B})=\mathrm{P}(\mathrm{A}\mathrm{or}\mathrm{B})=\mathrm{P}\left(\mathrm{A}\right)+\mathrm{P}\left(\mathrm{B}\right)$

Probability of English $\mathrm{P}\left(\mathrm{E}\right)=0.63$

Probability of French $\mathrm{P}\left(\mathrm{F}\right)=0.22$

Now,

$$\begin{gathered} \mathrm{P}(\mathrm{E}\mathrm{U}\mathrm{F})=\mathrm{P}\left(\mathrm{E}\right)+\mathrm{P}\left(\mathrm{F}\right) \\ \mathrm{P}(\mathrm{E}\mathrm{U}\mathrm{F})=0.63+0.22 \\ \mathrm{P}(\mathrm{E}\mathrm{U}\mathrm{F})=0.85 \end{gathered}$$

Hence, $0.85$ is the probability that the chosen person鈥檚 mother tongue is one of Canada鈥檚 official languages.