/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.44 Light through water Some college... [FREE SOLUTION] | 91影视

91影视

Light through water Some college students collected data on the intensity of light at various depths in a lake. Here is a scatterplot of their data:

a. At the top right is a scatterplot of the natural logarithm of light intensity versus depth. Based on this graph, explain why it would be reasonable to use an exponential model to describe the relationship between light intensity and depth.

b. Here is the computer output from a linear regression analysis of the transformed data. Give the equation of the least-squares regression line. Be sure to define any variables you use.

c. Use your model to predict the light intensity at a depth of 12 meters.

Short Answer

Expert verified

a). Scatter plot is not having strong curvature.

b). The equation of the least-squares regression line is lny^=6.78910-0.333021x.

c). The expected that the intensity is 16.3275 lumens at depth of 12 metre.

Step by step solution

01

Part (a) Step 1: Given Information

Given data:

02

Part (a) Step 2: Explanation

Presented the lack of substantial curvature in the given scatter plot, a linear model between the two scatter plot variables would be appropriate. As a result, a linear relationship between In(intensity) and depth is reasonable.

Expectations based on a general linear model Time and ln(intensity);

ln(intensity)=a+b(depth)

Taking the exponential

intensity=eln(intensity)

=ea+b(depth)=eaeb(depth)
03

Part (b) Step 1: Given Information

Given data:

04

Part (b) Step 2: Explanation

Least square regression line's general equation

y^=b0+b1x

In the row "constant" and the column "Coef" of the computer output, the calculated constant b0is mentioned.

b0=6.78910

In the row "Depth" and the column "Coef" of the computer output, the calculated slope b1 is mentioned.

b1=-0.333021

05

Part (b) Step 3: Explanation

Substituting the value of b0and b1

y^=b0+b1x

y^=6.78910-0.333021x

Wherex represents the current time and y is the ln (count)

role="math" localid="1654323193310" lny^=6.78910-0.333021x

Where x is representing the depth and y is representing the intensity.

06

Part (c) Step 1: Given Information

Given data:

07

Part (c) Step 2: Explanation

Substituting the value of x

lny^=6.78910-0.333021x

lny^=6.78910-0.333021(12)

=2.792848

Taking the exponential

y^=elny^

=e2.792848

=16.3275

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A scatterplot of yversus xshows a positive, nonlinear association. Two different transformations are attempted to try to linearize the association: using the logarithm of the y-values and using the square root of the y-values. Two least-squares regression lines are calculated, one that uses x to predict log(y) and the other that uses x to predict y. Which of the following would be the best reason to prefer the least-squares regression line that uses x to predict log(y)?

a. The value of r2is smaller.

b. The standard deviation of the residuals is smaller.

c. The slope is greater.

d. The residual plot has more random scatter.

e. The distribution of residuals is more Normal.

Exercises T12.4鈥揟12.8 refer to the following setting. An old saying in golf is 鈥淵ou drive for show and you putt for dough.鈥 The point is that good putting is more important than long driving for shooting low scores and hence winning money. To see if this is the case, data from a random sample of 69 of the nearly 1000 players on the PGA Tour鈥檚 world money list are examined. The average number of putts per hole (fewer is better) and the player鈥檚 total winnings for the previous season are recorded and a least-squares regression line was fitted to the data. Assume the conditions for
inference about the slope are met. Here is computer output from the regression analysis:

T12.4 By about how much does the sample slope typically vary from the population slope in repeated random samples of n=69 golfers?
a. 7,897,179
b. 1,698,371
c. 3,023,782
d. 281,777
e. 鈭4,139,198

If P(A)=0.2and P(B)=0.52 and events A and B are independent, what is P(A or B)?

a. 0.1248

b. 0.28

c. 0.6352

d. 0.76

e. The answer cannot be determined from the given information.

A distribution that represents the number of cars X parked in a randomly selected residential driveway on any night is given by

Given that there is at least 1 car parked on a randomly selected residential driveway on a particular night, which of the following is closest to the probability that exactly 4cars are parked on that driveway?

a. 0.10

b. 0.15

c. 0.17

d.0.75

e.0.90

The professor swims Here are data on the time (in minutes) Professor Moore takes to swim 2000yards and his pulse rate (beats per minute) after swimming on a random sample of 23days:

Is there convincing evidence of a negative linear relationship between Professor Moore鈥檚 swim time and his pulse rate in the population of days on which he swims2000yards?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.