91影视

$$\begin{gathered} \overline{x}=43.70 \\ MEDIN=42.00 \\ s=12.50 \\ {Q}_1=35.50 \\ {Q}_3=44.00 \end{gathered}$$

$Percentile=\frac{Numberofdatavaluesthatarelessthantheindividual\text{'}sdatavalue}{Totalnumberofdatavalues}脳100\%$

Relationship between feet and meter:

$3.2ft=1m鈬�1ft=\frac{1}{3.28}m$

The difference between the third and first quartiles is the interquartile range:

$$\begin{gathered} IQR=Q_3鈭�Q_1 \\ =44.00鈭�35.50 \\ =8.50 \end{gathered}$$

To convert the measurement from feet to meters, multiply by $3.28$:

$$\begin{gathered} \overline{x}=\frac{43.70}{3.28}=13.3232 \\ MEDIAN=\frac{42.00}{3.28}=12.8049 \\ s=\frac{12.50}{3.28}=3.8110 \\ IQR=\frac{8.50}{3.28}=2.5915 \end{gathered}$$

The distribution's shape would not be modified because every data value is translated in the same way, and so the data values would be distributed in the same way.

Every guess reduced the error distribution by $42.6$ percent. Then the mean goes down by the same amount:

$\overline{x}=43.70鈭�42.60=1.1$

Because the spread would not vary when the value reduced by the same amount, the standard deviation would remain unchanged.

$s=12.50$

The summary statistic has a value of $66$below n, indicating that there are $66$data values in the data set.

$4$dots are to the right of $63$on the dot plot, and $1$ dot is related with $63$implying that $66-4-1=61$dots of the $66$dots are to the left of $63$

Required percentile

$Percentile=\frac{Numberofdatavaluesthatarelessthantheindividual\text{'}sdatavalue}{Totalnumberofdatavalues}脳100\%$

$$\begin{gathered} =\frac{61}{66}脳100\% \\ =0.92脳100\% \\ =92\% \end{gathered}$$

Therefore the percentile associated with $63$feet is the $92nd$percentile.