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Watch the salt! Refer to Exercise 55About what percent of the meals

ordered contained between 1200 mg and 1800 mg of sodium?

Short Answer

Expert verified

Around 28.98% of the meals ordered contained between 1200 mg and 1800 mg of sodium.

Step by step solution

01

Given information

Daily allowance,x=1200mgor1800mg

Mean,=2000mg

Standard deviation,=500mg

02

Concept

The formula used:z=x

03

Calculation

Calculate the Z 鈭 score,

z=x=1200mg2000mg500mg=1.60

or

z=x=1800mg2000mg500mg=0.40

To find the equivalent probability, use the normal probability table in the appendix.

In the typical normal probability table forP(z<1.60), look at the row that starts with -1.6 and the column that starts with.00.

Or

The usual normal probability table forP(z<0.40)has a row that starts with -0.4 and a column that starts with.00.

P(1200<x<1800)=P(1.60<z<0.40)=P(z<0.40)P(z<1.60)=0.34460.0548=0.2898=28.98%

Therefore,

Around 28.98% of the meals ordered contained between 1200 mg and 1800 mg of sodium.

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