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Neither of these transformations changes the shape of the distribution.

The distribution's apex is to the left, and the distribution is skewed to the right, with a tail of more odd values to the right in the graph.

Because the median is resistant while the mean is not, the mean is more influenced by the right-skewed distribution's extremely high values.

Because both the mean and the median are influenced by unusually high values in the right-skewed distribution, one measure impacts more than the other, neither the median nor the mean is predicted to reside at the distribution's peak.

Despite the fact that the mean is higher than the median, neither is at the apex.

As a result, $C$ denotes the mean and $B$ denotes the median.

The graph on $B\text{'}$s left is the mirror image of the graph to $B\text{'}s$ right. The distribution is thus symmetric.

Both the median and the mean should be at the centre of the distribution for the distribution to be symmetric (at point $B$).

As a result, $B$ stands for both the mean and the median.