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Losing weight A Gallup poll asked a random sample of U.S. adults, 鈥淲ould you like to lose weight?鈥 Based on this poll, the 95%confidence interval for the population

proportion who want to lose weight is (0.56,0.62).

a. Interpret the confidence interval.

b. What is the point estimate that was used to create the interval? What is the margin of error?

c. Based on this poll, Gallup claims that more than half of U.S. adults want to lose weight. Use the confidence interval to evaluate this claim.

Short Answer

Expert verified

a. There is 95%assurance that US adults who wish to lose weight lie in given interval.

b. Point estimation is 0.59and margin of error is 0.03.

c. It is a convincing evidence.

Step by step solution

01

Given Information

It is given that 95%confidence interval for proportion is(0.56,0.62)

02

Concept Used

Formula Used arep^=UCL+LCL2andME=UCL-LCL2

03

a. Interpreting Confidence Interval

It refers to 95%assurance that US adults proportion who wish to lose weight lie between0.56-0.62. Others do not wish to lose weight.

04

b. Point Estimate and Margin of Error

Point Estimation: It is given by p^=0.56+0.622=0.59

It lies halfway of confidence interval. Point estimate is average of boundaries of given interval.

Margin of Error: It is given by ME=0.62-0.562=0.03

It is half the difference of confidence interval.

05

c. Evaluating the claim

After the above observation and given data, it can be observed that population proportion who wish to lose weight is 0.50.

Hence, there is a convincing evidence that more than half of US adults who wish to lose weight.

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Most popular questions from this chapter

More Oranges:The gardener in the previous exercise randomly selects 20

mandarin oranges from the tree and counts the number of seeds in each orange. Here are the data:

a. Graph the data using a dot plot.

b. Based on your graph, is it plausible that the number of seeds from oranges on this tree follows a distribution that is approximately Normal? Explain your answer.

Scientists collect data on the blood cholesterol levels (milligrams per deciliter of blood) of a random sample of 24laboratory rats. A 95%confidence interval for the mean blood cholesterol level is 80.2to 89.8. Which of the following would cause the most worry about the validity of this interval?

a. There is a clear outlier in the data.

b. A stem plot of the data shows a mild right skew.

c. You do not know the population standard deviation .

d. The population distribution is not exactly Normal.

e. None of these are a problem when using a t interval.

You want to compute a 90%confidence interval for the mean of a population with an unknown population standard deviation. The sample size is 30. What critical value should you use for this interval?

a. 1.645

b. 1.699

c. 1.697

d. 1.96

e. 2.045

Age and video games Refer to Exercise 41. The study also estimated that 67% of adults aged 1829play video games, but only 25%of adults aged 65and older play video games.

a. Explain why you do not have enough information to give confidence intervals for these two age groups separately.

b. Do you think a 95% confidence interval for adults aged 1829 would have a larger or smaller margin of error than the estimate from Exercise 41? Explain your answer.

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a. 2.177

b. 2.183

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d. 2.500

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