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PTC is a substance that has a strong bitter taste for some people and is tasteless for others. The ability to taste \(\mathrm{PTC}\) is inherited. About \(75 \%\) of Italians can taste \(\mathrm{PTC}\), for example. You want to estimate the proportion of Americans who have at least one Italian grandparent and who can taste PTC. (a) How large a sample must you test to estimate the proportion of PTC tasters within 0.04 with \(90 \%\) confidence? Answer this question using the \(75 \%\) estimate as the guessed value for \(\hat{p}\). (b) Answer the question in part (a) again, but this time use the conservative guess \(\hat{p}=0.5 .\) By how much do the two sample sizes differ?

Short Answer

Expert verified
Sample sizes: 213 for \(\hat{p} = 0.75\), 424 for \(\hat{p} = 0.5\). Difference: 211.

Step by step solution

01

Understand the Problem

We need to determine the sample size for a proportion estimate within a margin of error of 0.04 at 90% confidence. We will use the estimates \( \hat{p} = 0.75 \) and \( \hat{p} = 0.5 \) separately to calculate the sample sizes.
02

Use the Sample Size Formula

The formula for the sample size required to estimate a population proportion \( p \) with a given margin of error \( E \) and confidence level \( Z \) is: \[ n = \left( \frac{Z^2 \times \hat{p} \times (1 - \hat{p})}{E^2} \right) \] where \( Z \) is the z-value corresponding to the desired confidence level, and \( E \) is the margin of error.
03

Find the Z-value

For a 90% confidence level, the z-score (Z-value) is approximately 1.645.
04

Calculate Sample Size with \(\hat{p} = 0.75\)

Substituting \( \hat{p} = 0.75 \), \( E = 0.04 \), and \( Z = 1.645 \) into the formula, we find \[ n = \left( \frac{1.645^2 \times 0.75 \times (1 - 0.75)}{0.04^2} \right) \approx 212.79. \] Rounding up, we need a sample size of 213.
05

Calculate Sample Size with \(\hat{p} = 0.5\)

Substituting \( \hat{p} = 0.5 \) into the formula, we find \[ n = \left( \frac{1.645^2 \times 0.5 \times (1 - 0.5)}{0.04^2} \right) \approx 423.12. \] Rounding up, we need a sample size of 424.
06

Compare the Sample Sizes

The difference between the two calculated sample sizes is \( 424 - 213 = 211 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Estimation
Proportion estimation is a technique used to predict the proportion of a population with a particular characteristic. In survey studies like the PTC-tasting example, we start with a guessed proportion, \( \hat{p} \), which represents our best estimate of the true proportion of the population. This estimate is usually based on prior data or any existing information about the population.
For instance, in our exercise, we begin by assuming that \( 75\% \) of those with at least one Italian grandparent can taste PTC. This value serves as our initial guess, \( \hat{p} = 0.75 \). However, it is also wise to sometimes use a more cautious estimate like \( \hat{p} = 0.5 \), known as the conservative approach, as this maximizes the uncertainty and covers the worst-case scenario when no prior knowledge is available.
This guessed proportion, or prior estimate, is crucial as it directly affects the calculated sample size for studies aiming to estimate proportions.
Margin of Error
The margin of error signifies the degree of accuracy we desire in estimating the population proportion. It defines the range within which the true proportion is expected to lie. A smaller margin of error generally demands a larger sample size to ensure that our estimation is accurate to the degree we require.
In the problem discussed, the margin of error is set at \( 0.04 \), meaning our proportion estimate from the sample should be within \( 4\% \) of the true population proportion. Balancing this accuracy with practical considerations is important, as striving for a very small margin may often result in impractically large sample sizes, increasing time and resource expenditure.
Understanding the desired precision helps in finding the right balance between the feasibility of the study and the reliability of its results.
Confidence Level
The confidence level expresses how certain we are that our population proportion estimate lies within the margin of error. It is usually denoted as a percentage, signifying the likelihood that the estimate falls within this range if the process were repeated multiple times.
For the PTC-tasting study, a \( 90\% \) confidence level is selected, indicating a high degree of confidence that our sample's results reflect the true population proportion. Higher confidence levels can require larger sample sizes because greater certainty in the results is achieved by sampling more people.
The confidence level is intertwined with both the z-score and the margin of error, impacting the overall study design and how results can be interpreted.
Z-score
Z-scores are a statistical measure that reflects how many standard deviations an element is from the mean. In the context of confidence intervals and sample size estimation, z-scores are used to indicate the confidence level in standard normal distribution terms.
For a \( 90\% \) confidence level, the corresponding z-score is approximately \( 1.645 \). Calculating z-scores accurately is crucial for determining how wide the confidence interval should be. This, in turn, dictates the sample size required to achieve a desired confidence level given a certain margin of error.
The z-score is integrated into the sample size formula, multiplying the guessed proportion and its complement, which highlights its role as an essential component in obtaining precise and valid survey outcomes.

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Most popular questions from this chapter

A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean is \(\bar{x}=31.25\) minutes, and the standard deviation is \(s_{x}=21.88\) minutes. What is the standard error of the mean? Interpret this value in context.

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