/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Scores on the mathematics part o... [FREE SOLUTION] | 91Ó°ÊÓ

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Scores on the mathematics part of the SAT exam in a recent year were roughly Normal with mean 515 and standard deviation 114 . You choose an SRS of 100 students and average their SAT Math scores. Suppose that you do this many, many times. Which of the following are the mean and standard deviation of the sampling distribution of \(\bar{x} ?\) (a) \(\quad\) Mean \(=515, \mathrm{SD}=114\) (b) \(\quad\) Mean \(=515, \mathrm{SD}=114 / \sqrt{100}\) (c) \(\quad\) Mean \(=515 / 100, \mathrm{SD}=114 / 100\) (d) \(\quad\) Mean \(=515 / 100, \mathrm{SD}=114 / \sqrt{100}\) (e) Cannot be determined without knowing the 100 scores.

Short Answer

Expert verified
(b) Mean = 515, SD = 114 / √100.

Step by step solution

01

Understanding the Concept of a Sampling Distribution

The problem involves the concept of a sampling distribution, particularly of the sample mean \( \bar{x} \). When samples are taken randomly and repeatedly from a population, the distribution of an averaged sample forms its own distribution, called the sampling distribution.
02

Mean of the Sampling Distribution

The mean of the sampling distribution of the sample mean \( \bar{x} \) is equal to the mean of the population from which the sample is drawn. Hence, the mean of \( \bar{x} \) is 515.
03

Standard Deviation of the Sampling Distribution (Standard Error)

The standard deviation of the sampling distribution of \( \bar{x} \), also known as the standard error (SE), is calculated as the population standard deviation divided by the square root of the sample size. Here it is \( \frac{114}{\sqrt{100}} = \frac{114}{10} = 11.4 \).
04

Matching the Answer With the Options

We now compare our results: mean = 515 and standard deviation = 11.4 with the available choices. The correct answer is (b) Mean \( = 515 \), SD \( = \frac{114}{\sqrt{100}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Sample Means
To understand the concept of the mean of sample means, we first need to comprehend what a sample mean represents. When we collect **samples** from a population and compute their averages, these averages are known as **sample means**. In statistical terms, if you repeatedly take *different* samples from the same population, the average of all these sample means will equal the **population mean**.

This remarkable property is called the **mean of sample means**, and it simplifies various statistical calculations. In the SAT Math score scenario, the population mean is given as 515. No matter how many samples you take, their average will still reflect the population's central tendency.
  • Sample means provide a reliable estimate of the population mean.
  • This concept emphasizes consistency across samples, regardless of variance in individual samples.
This principle is useful when drawing conclusions about a population without measuring every individual item, helping us to make confident predictions and analyses.
Standard Error
**Standard error** plays a central role in understanding statistical accuracy. It is the measure of the variability or "spread" of the sample means in a sampling distribution. When the population standard deviation and the sample size are known, standard error can easily be calculated.

The formula is straightforward: divide the population standard deviation by the square root of the sample size:\[SE = \frac{\sigma}{\sqrt{n}}\]where \(\sigma\) is the population standard deviation and \(n\) is the sample size.

In the SAT Math case, with a population standard deviation of 114 and a sample size of 100, the standard error is calculated as:\[SE = \frac{114}{\sqrt{100}} = 11.4\]
  • Standard error allows us to determine how much sample means deviate from the true population mean.
  • A smaller standard error indicates that sample means are closely clustered around the population mean.
By considering the standard error, statisticians are able to make more precise estimates about the population from which a sample is drawn.
Central Limit Theorem
The **central limit theorem** is a fundamental concept in statistics that describes how the distribution of sample means becomes more normal as the sample size increases. Even if the population distribution is not normal, the theorem holds true under certain conditions, particularly with larger sample sizes.

Key implications of the central limit theorem include:
  • **Normality:** When the sample size is sufficiently large, the sampling distribution of the sample mean is approximately normal.
  • **Sample Size:** Larger sample sizes typically lead to a clearer approximation of the normal distribution.
  • **Application:** It provides the foundation for constructing confidence intervals and hypothesis testing.
In our SAT Math example, although the population distribution of scores is normal, the central limit theorem reassures that even if it weren’t, a large enough sample size (like 100) would yield a normally shaped sampling distribution. This theorem is invaluable for simplifying the analysis and interpretation of data, making it crucial for more advanced statistical applications and analyses.

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Most popular questions from this chapter

At a particular college, \(78 \%\) of all students are receiving some kind of financial aid. The school newspaper selects a random sample of 100 students and \(72 \%\) of the respondents say they are receiving some sort of financial aid. Which of the following is true? (a) \(78 \%\) is a population and \(72 \%\) is a sample. (b) \(72 \%\) is a population and \(78 \%\) is a sample. (c) \(78 \%\) is a parameter and \(72 \%\) is a statistic. (d) \(72 \%\) is a parameter and \(78 \%\) is a statistic. (e) \(78 \%\) is a parameter and 100 is a statistic.

Songs on an iPod David's iPod has about 10,000 songs. The distribution of the play times for these songs is heavily skewed to the right with a mean of 225 seconds and a standard deviation of 60 seconds. Suppose we choose an SRS of 10 songs from this population and calculate the mean play time \(\bar{x}\) of these songs. What are the mean and the standard deviation of the sampling distribution of \(\bar{x}\) ? Explain.

Predict the election A polling organization plans to ask a random sample of likely voters who they plan to vote for in an upcoming election. The researchers will report the sample proportion \(\hat{p}\) that favors the incumbent as an estimate of the population proportion \(p\) that favors the incumbent. Explain to someone who knows little about statistics what it means to say that \(\hat{p}\) is an unbiased estimator of \(p\).

Increasing the sample size of an opinion poll will reduce the (a) bias of the estimates made from the data collected in the poll. (b) variability of the estimates made from the data collected in the poll. (c) effect of nonresponse on the poll. (d) variability of opinions in the sample. (e) variability of opinions in the population.

Which of the following are the mean and standard deviation of the sampling distribution of the sample proportion \(\hat{p} ?\) (a) \(\quad\) Mean \(=0.30, \mathrm{SD}=0.017\) (b) \(\quad\) Mean \(=0.30, \mathrm{SD}=0.55\) (c) Mean \(=0.30, \mathrm{SD}=0.0003\) (d) Mean \(=225, \mathrm{SD}=12.5\) (e) Mean \(=225, \mathrm{SD}=157.5\)

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