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91Ó°ÊÓ

"Checking for survey errors One way of checking the effect of undercoverage, nonresponse, and other sources of error in a sample survey is to compare the sample with known facts about the population. About \(12 \%\) of American adults identify themselves as black. Suppose we take an SRS of 1500 American adults and let \(X\) be the number of blacks in the sample. (a) Show that \(X\) is approximately a binomial random variable. (b) Check the conditions for using a Normal approximation in this setting. (c) Use a Normal distribution to estimate the probability that the sample will contain between 165 and 195 blacks.

Short Answer

Expert verified
The probability is approximately 0.8064.

Step by step solution

01

Verify Binomial Distribution

Define the random variable \(X\) as the number of black adults in a simple random sample (SRS) of 1500 American adults. \(X\) is a binomial random variable with parameters \(n = 1500\) and \(p = 0.12\), where \(n\) is the number of trials and \(p\) is the probability of success (an adult identifying as black). \(X\) counts the number of successes (black adults), and since it meets the criteria for a binomial distribution (fixed number of independent trials, two possible outcomes per trial), \(X\) is a binomial random variable.
02

Check Conditions for Normal Approximation

To use the Normal approximation for a binomial distribution, both \(np\) and \(n(1-p)\) should be greater than or equal to 10. Calculate \(np = 1500 \times 0.12 = 180\) and \(n(1-p) = 1500 \times 0.88 = 1320\). Both values are much greater than 10, thus a Normal approximation is appropriate.
03

Apply Normal Approximation

Use the Normal distribution to approximate \(X\) by calculating its mean and standard deviation. The mean of the distribution is \(\mu = np = 180\). The standard deviation is \(\sigma = \sqrt{np(1-p)} = \sqrt{1500\times0.12\times0.88} \approx 11.495\). Convert the binomial distribution to a Normal distribution with these parameters.
04

Estimate Probability Using Normal Distribution

To find the probability that \(X\) is between 165 and 195, convert these to standard Normal variables using \(Z = \frac{X - \mu}{\sigma}\). For \(X = 165\), \(Z = \frac{165 - 180}{11.495} \approx -1.30\). For \(X = 195\), \(Z = \frac{195 - 180}{11.495} \approx 1.30\). Use the standard Normal distribution table to find the probabilities: \(P(Z < 1.30) \approx 0.9032\) and \(P(Z < -1.30) \approx 0.0968\). The probability that \(X\) is between 165 and 195 is \(P(-1.30 < Z < 1.30) = 0.9032 - 0.0968 = 0.8064\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Approximation
The normal approximation is a useful technique when dealing with binomial distributions, especially for sample sizes that are considerably large. Binomial distribution is a type of discrete probability distribution. However, as the number of trials increases, calculating probabilities directly using the binomial formula can become cumbersome. This is where the normal approximation provides an elegant solution.

To apply a normal approximation to a binomial distribution, we first need to check if the sample size is big enough. The rule of thumb is that both the expected number of successes, \( np \), and failures, \( n(1-p) \), should be at least 10. This ensures that the distribution is adequately symmetric.

Here's the process, in short:
  • Calculate \( np \) and \( n(1-p) \) to confirm they are larger than 10.
  • Use the binomial mean \( \mu = np \) and standard deviation \( \sigma = \sqrt{np(1-p)} \) for the normal distribution.
Once the conditions are met, the normal distribution can approximate the binomial distribution using these parameters.
Probability Estimation
Probability estimation in the context of surveys and random samples often involves determining the likelihood of certain outcomes within a population. When working with binomial distributions, such as in the survey of American adults identifying as black, one may use probability estimation to predict sample outcomes.

Here's how probability estimation works:
  • First, identify your parameters: number of trials \( n \) and probability of success \( p \).
  • Next, calculate the mean \( \mu = np \) and standard deviation \( \sigma = \sqrt{np(1-p)} \).
  • Use these to describe the normal approximation of your distribution.
For example, if you want to know the probability of finding between 165 and 195 black adults in a sample of 1500, you would convert these numbers to Z-scores in the standard normal distribution. Using Z-score tables or a calculator, you can find the probabilities associated with these Z-scores, allowing for accurate probability estimation.
Sample Survey Errors
Sample survey errors can significantly affect the accuracy and reliability of survey results. When conducting surveys, issues such as undercoverage and nonresponse need careful consideration.

Here's a brief explanation of these errors:
  • **Undercoverage**: This occurs when some groups are inadequately represented in the sample. It can lead to biased results that do not accurately reflect the entire population.
  • **Nonresponse**: This happens when some individuals from a selected sample do not respond to the survey. Nonresponse can skew results, especially if the nonrespondents have different characteristics from the respondents.
To mitigate these errors, researchers compare the sample with known facts about the population, ensuring that the sample parameters align closely with the population parameters. The use of statistical methods like normal approximation helps in understanding the magnitude and direction of potential errors, providing a statistical measure to account for them.

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Most popular questions from this chapter

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