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Kids and toys In an experiment on the behavior of young children, each subject is placed in an area with five toys. Past experiments have shown that the probability distribution of the number \(X\) of toys played with by a randomly selected subject is as follows: $$ \begin{array}{lcccccc} \hline \text { Number of toys } x_{i}: & 0 & 1 & 2 & 3 & 4 & 5 \\ \text { Probability } p_{i} & 0.03 & 0.16 & 0.30 & 0.23 & 0.17 & 0.11 \\ \hline \end{array} $$ (a) Write the event "plays with at most two toys" in terms of \(X\). What is the probability of this event? (b) Describe the event \(X>3\) in words. What is its probability? What is the probability that \(X \geq 3 ?\)

Short Answer

Expert verified
(a) \( P(X \leq 2) = 0.49 \); (b) 'Plays with more than 3 toys', \( P(X > 3) = 0.28 \), \( P(X \geq 3) = 0.51 \).

Step by step solution

01

Define Event for Part (a)

The event 'plays with at most two toys' is represented by the condition \( X \leq 2 \). This includes the events where the child plays with 0, 1, or 2 toys.
02

Calculate Probability for Part (a)

To find the probability of playing with at most two toys, add the probabilities for \( X = 0 \), \( X = 1 \), and \( X = 2 \): \( P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.03 + 0.16 + 0.30 = 0.49 \).
03

Define Event for Part (b)

The event \( X > 3 \) in words means 'the child plays with more than 3 toys'. This event includes playing with 4 or 5 toys.
04

Calculate Probability for \( X > 3 \)

Add the probabilities for \( X = 4 \) and \( X = 5 \) to find \( P(X > 3) \): \( P(X > 3) = P(X = 4) + P(X = 5) = 0.17 + 0.11 = 0.28 \).
05

Calculate Probability for \( X \geq 3 \)

To find the probability that \( X \geq 3 \), add the probabilities for \( X = 3 \), \( X = 4 \), and \( X = 5 \): \( P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) = 0.23 + 0.17 + 0.11 = 0.51 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
A random variable is a fundamental concept in probability theory. It is a variable that takes on values determined by the outcomes of a random phenomenon. In our exercise, the random variable is represented by the letter \(X\), which denotes the number of toys played with by a child. This implies that as each child is observed interacting with toys, \(X\) changes according to their behavior in that specific instance.
Random variables are broadly categorized into two types: discrete and continuous. The variable \(X\) in this exercise is discrete because it only assumes specific values, namely 0, 1, 2, 3, 4, or 5, corresponding to the count of toys.
When working with random variables, it's crucial to establish what each value represents. Here:
  • \(X = 0\): No toys played with.
  • \(X = 1\): One toy played with.
  • \(X = 2\): Two toys played with.
  • ...and so on up to \(X = 5\).
Understanding the nature of random variables helps in formulating events, such as determining the probability of playing with certain numbers of toys.
Probability Calculation
Probability calculation involves determining the likelihood of various outcomes related to random variables. In our exercise, we calculate probabilities for different possible behaviors of children interacting with toys, which is crucial to predict and understand their behavior.

For example, to find the probability of a child playing with at most two toys, we add the probabilities of \(X\) taking values 0, 1, and 2:
  • \(P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)\)
  • \(P(X \leq 2) = 0.03 + 0.16 + 0.30 = 0.49\)

This adds up to 0.49, meaning there is a 49% chance that a child will play with two or fewer toys.
Similarly, calculating for \(X > 3\), we consider \(X = 4\) or \(X = 5\):
  • \(P(X > 3) = P(X = 4) + P(X = 5)\)
  • \(P(X > 3) = 0.17 + 0.11 = 0.28\)

This means a 28% likelihood that more than three toys are played with.
Such calculations help derive useful insights and validate hypotheses about behavioral patterns under study.
Discrete Distribution
Discrete distribution is another key concept in probability and statistics. It refers to a probability distribution where the random variable can only take on a finite or countably infinite set of values. In our exercise, the number of toys \(X\) can take values from 0 to 5, forming a discrete distribution.

To understand a discrete distribution, we need a probability mass function (PMF), which provides:
  • The probability of obtaining each possible value of the random variable.

In our example, the PMF is given as:
  • \(P(X = 0) = 0.03\)
  • \(P(X = 1) = 0.16\)
  • \(P(X = 2) = 0.30\)
  • \(P(X = 3) = 0.23\)
  • \(P(X = 4) = 0.17\)
  • \(P(X = 5) = 0.11\)

This information allows researchers to predict the frequency or likelihood of the random variable's outcomes.
A deep understanding of discrete distributions is vital as it empowers us to handle any structured uncertainty involving countable scenarios, thus facilitating the decision-making process based on statistical data.

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