/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Exercises 59 to 60 refer to the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Exercises 59 to 60 refer to the following setting. For their final project, a group of AP \(^{\otimes}\) Statistics students investigated the following question: "Will changing the rating scale on a survey affect how people answer the question?" To find out, the group took an SRS of 50 students from an alphabetical roster of the school's just over 1000 students. The first 22 students chosen were asked to rate the cafeteria food on a scale of 1 (terrible) to 5 (excellent). The remaining 28 students were asked to rate the cafeteria food on a scale of 0 (terrible) to 4 (excellent). Here are the data: $$ \begin{array}{lcccrc} &{1 \text { to 5 scale }} \\ \text { Rating } & 1 & 2 & 3 & 4 & 5 \\ \text { Frequency } & 2 & 3 & 1 & 13 & 3 \\ \hline & {0 \text { to 4 scale }} \\ \text { Rating } & 0 & 1 & 2 & 3 & 4 \\ \text { Frequency } & 0 & 0 & 2 & 18 & 8 \\ \hline \end{array} $$ $$ \text { Design and analysis }(4.2) $$ (a) Was this an observational study or an experiment? Justify your answer. (b) Explain why it would not be appropriate to perform a chi-square test in this setting.

Short Answer

Expert verified
(a) It's an experiment; the rating scale is changed deliberately. (b) Chi-square isn't appropriate due to differing scales and non-comparable categories.

Step by step solution

01

Identify Study Type

In part (a), we need to determine if the given scenario is an observational study or an experiment. In an observational study, researchers observe and measure outcomes without imposing any treatment or change. In an experiment, researchers deliberately impose treatments or changes to observe their effects. In this scenario, the students are imposing two different rating scales (1-5 and 0-4) on different groups of students to observe the impact on their responses. Thus, this qualifies as an experiment because the rating scale is being deliberately changed to investigate its effects.
02

Assess Appropriateness of Chi-Square Test

For part (b), we must evaluate why a chi-square test is not suitable here. A chi-square test is used to determine if there is a significant association between categorical variables or if observed frequencies in categories fit a specified distribution. In this context, the ratings from two different scales (1-5 and 0-4) are not truly comparable because each scale represents a different conceptual framework, even if numerically similar. Thus, the categorical nature and lack of commonality between these two scales prevent a meaningful application of the chi-square test, as they lead to non-comparable data distributions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Observation vs Experimentation
When we look at the study process, a key distinction is whether the approach taken is observational or experimental. In an observational study, the researcher simply observes the subjects without any interference. This means they document what naturally occurs without altering variables or imposing any new conditions. It's like being a silent audience member in a play.

In contrast, experimentation involves actively changing one variable to see if it causes an effect on another. Typically, the researcher imposes a treatment or condition on the subjects. For instance, our AP Statistics students decided to modify the rating scales from 1 to 5 and from 0 to 4 to assess their influence on the ratings given by students. Therefore, this study is an experiment. The students deliberately changed the scales, aiming to determine if it impacts the way subjects rate cafeteria food. This manipulation characterizes the study as an experiment.
Chi-Square Test
The chi-square test is a statistical tool used to examine if there is a significant association between categorical variables. It helps us understand if observed data deviate from the expected data under a given hypothesis. It's vital to ensure that the categories being compared are similar enough to yield meaningful results.

In our AP Statistics scenario, students were surveyed using two distinct rating scales. Specifically, one group rated using a 1 to 5 scale and the other using a 0 to 4 scale. Even though these seem similar, they represent different measurable frameworks. Each scale has additional nuances and impacts on data interpretation, which means they don't form a common basis for comparison. That makes the chi-square test inappropriate in this case. The scales create non-comparable categories, disrupting the assumptions needed for a chi-square analysis.
Survey Design
Executing a well-thought-out survey design is crucial to gathering reliable and meaningful data. In survey research, clarity, consistency, and unbiased questions are paramount. It starts with determining the aim of the survey, which in this context is to find out if the rating scale affects student responses about cafeteria food.

The students selected a simple random sample (SRS) from the school roster. This method is a robust way to ensure every participant has an equal chance of being chosen, which minimizes selection bias. The next step was to administer the survey questions with clear and straightforward scales. The survey design here cleverly implements two rating scales to explore their effect. But, it's essential to note that every element, from question wording to scale definition, should remain consistent within each subset to avoid confusing participants.
Rating Scales
Rating scales are commonly used tools in surveys that allow respondents to express their perception or evaluation neatly and quantitatively. Commonly, they offer a range, in this study from 1 to 5 or 0 to 4, that corresponds to a gradient of opinions from negative to positive.

Each rating scale presents unique calibration and interpretation, which affects the survey's outcomes. For example, a 1 to 5 scale may imply different strength or extremes of opinion than a 0 to 4 scale. While both aim to gauge satisfaction with the cafeteria food, their differing start and endpoints can shift perception slightly. Thus, the design using varied scales thoughtfully examines their impact on the data. However, for accurate comparisons across scales, adjustments or considerations regarding these inherent differences need to be made.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How are schools doing? The nonprofit group Public Agenda conducted telephone interviews with three randomly selected groups of parents of high school children. There were 202 black parents, 202 Hispanic parents, and 201 white parents. One question asked was "Are the high schools in your state doing an excellent, good, fair, or poor job, or don't you know enough to say?" Here are the survey results: \({ }^{14}\) $$ \begin{array}{lccc} \hline & \begin{array}{c} \text { Black } \\ \text { parents } \end{array} & \begin{array}{c} \text { Hispanic } \\ \text { parents } \end{array} & \begin{array}{c} \text { White } \\ \text { parents } \end{array} \\ \text { Excellent } & 12 & 34 & 22 \\ \text { Good } & 69 & 55 & 81 \\ \text { Fair } & 75 & 61 & 60 \\ \text { Poor } & 24 & 24 & 24 \\ \text { Don't know } & 22 & 28 & 14 \\ \text { Total } & 202 & 202 & 201 \\ \hline \end{array} $$ (a) Calculate the conditional distribution (in proportions) of responses for each group of parents. (b) Make an appropriate graph for comparing the conditional distributions in part (a). (c) Write a few sentences comparing the distributions of responses for the three groups of parents.

You say tomato The paper "linkage Studies of the Tomato" (Transactions of the Canadian Institute, 1931 ) reported the following data on phenotypes resulting from crossing tall cut-leaf tomatoes with dwarf potato-leaf tomatoes. We wish to investigate whether the following frequencies are consistent with genetic laws, which state that the phenotypes should occur in the ratio 9: 3: 3: 1 . $$ \begin{array}{lcccc} \hline \text { Phenotype: } & \begin{array}{c} \text { Tall } \\ \text { cut } \end{array} & \begin{array}{c} \text { Tall } \\ \text { potato } \end{array} & \begin{array}{c} \text { Dwarf } \\ \text { cut } \end{array} & \begin{array}{c} \text { Dwarf } \\ \text { potato } \end{array} \\ \text { Frequency: } & 926 & 288 & 293 & 104 \\ \hline \end{array} $$ Assume that the conditions for inference were met. Carry out an appropriate test of the proposed genetic model. What do you conclude?

Refer to the following setting. The National Longitudinal Study of Adolescent Health interviewed a random sample of 4877 teens (grades 7 to 12 ). One question asked was "What do you think are the chances you will be married in the next ten years?" Here is a two-way table of the responses by gender: \({ }^{28}\) $$ \begin{array}{lcc} \hline & \text { Female } & \text { Male } \\ \text { Almost no chance } & 119 & 103 \\ \text { Some chance, but probably not } & 150 & 171 \\ \text { A 50-50 chance } & 447 & 512 \\ \text { A good chance } & 735 & 710 \\ \text { Almost certain } & 1174 & 756 \\ \hline \end{array} $$ The appropriate null hypothesis for performing a chi-square test is that (a) equal proportions of female and male teenagers are almost certain they will be married in 10 years. (b) there is no difference between the distributions of female and male teenagers' opinions about marriage in this sample. (c) there is no difference between the distributions of female and male teenagers' opinions about marriage in the population. (d) there is no association between gender and opinion about marriage in the sample. (e) there is no association between gender and opinion about marriage in the population.

How to quit smoking It's hard for smokers to quit. Perhaps prescribing a drug to fight depression will work as well as the usual nicotine patch. Perhaps combining the patch and the drug will work better than either treatment alone. Here are data from a randomized, double-blind trial that compared four treatments. \({ }^{19} \mathrm{~A}\) "success" means that the subject did not smoke for a year following the beginning of the study. $$ \begin{array}{llcc} \hline \text { Group } & \text { Treatment } & \text { Subjects } & \text { Successes } \\ 1 & \text { Nicotine patch } & 244 & 40 \\ 2 & \text { Drug } & 244 & 74 \\ 3 & \text { Patch plus drug } & 245 & 87 \\ 4 & \text { Placebo } & 160 & 25 \\ \hline \end{array} $$ (a) Summarize these data in a two-way table. Then compare the success rates for the four treatments. (b) Explain in words what the null hypothesis \(H_{0}: p_{1}=\) \(p_{2}=p_{3}=p_{4}\) says about subjects' smoking habits. (c) Do the data provide convincing evidence of a difference in the effectiveness of the four treatments at the \(\alpha=0.05\) significance level?

Refer to the following setting. The manager of a high school cafeteria is planning to offer several new types of food for student lunches in the following school year. She wants to know if each type of food will be equally popular so she can start ordering supplies and making other plans. To find out, she selects a random sample of 100 students and asks them, "Which type of food do you prefer: Asian food, Mexican food, pizza, or hamburgers?" Here are her data: $$ \begin{array}{lcccc} \hline \text { Type of Food: } & \text { Asian } & \text { Mexican } & \text { Pizza } & \text { Hamburgers } \\ \text { Count: } & 18 & 22 & 39 & 21 \\ \hline \end{array} $$ The \(P\) -value for a chi-square test for goodness of fit is \(0.0129 .\) Which of the following is the most appropriate conclusion? (a) Because 0.0129 is less than \(\alpha=0.05\), reject \(H_{0}\). There is convincing evidence that the food choices are equally popular. (b) Because 0.0129 is less than \(\alpha=0.05\), reject \(H_{0}\). There is not convincing evidence that the food choices are equally popular. (c) Because 0.0129 is less than \(\alpha=0.05\), reject \(H_{0}\). There is convincing evidence that the food choices are not equally popular. (d) Because 0.0129 is less than \(\alpha=0.05,\) fail to reject \(H_{0}\). There is not convincing evidence that the food choices are equally popular. (e) Because 0.0129 is less than \(\alpha=0.05\), fail to reject \(H_{0}\). There is convincing evidence that the food choices are equally popular.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.