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The composition of the earth鈥檚 atmosphere may have changed over time. To try to discover the nature of the atmosphere long ago, we can examine the gas in bubbles inside ancient amber. Amber is tree resin that has hardened and been trapped in rocks. The gas in bubbles within amber should be a sample of the atmosphere at the time the amber was formed. Measurements on 9 specimens of amber from the late Cretaceous era (75 to 95 million years ago) give these percent of nitrogen:

63.4 65.0 64.4 63.3 54.8 64.5 60.8 49.1 51.0

Explain why we should not carry out a one-sample t test in this setting.

Short Answer

Expert verified

The selection of the sample is done through a simple random technique hence we should not carry out a one-sample t test in this setting.

Step by step solution

01

Introduction

A test statistic is a statistic utilized in statistical hypothesis testing. A hypothesis test is typically specified as far as a test statistic, considered as a numerical synopsis of an informational collection that decreases the information to one worth that can be utilized to play out the hypothesis test.

02

Explanation

Given,

63.4鈥呪赌呪赌呪赌65.0鈥呪赌呪赌呪赌64.4鈥呪赌呪赌呪赌63.3鈥呪赌呪赌呪赌54.8鈥呪赌呪赌呪赌64.5鈥呪赌呪赌呪赌60.8鈥呪赌呪赌呪赌49.1鈥呪赌呪赌呪赌51.0

We cannot carry out a one-sample t-test in this setting as a selection of the sample is done through a simple random technique and the sample size is 9which is less than 30. Hence the normality assumption is not satisfied.

Hence the selection of the sample is done through a simple random technique and we should not carry out a one-sample t test in this setting.

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Most popular questions from this chapter

The z statistic for a test of H0 :p = 0.4 versus Ha : p > 0.4 is z = 2.43. This test is

(a) not significant at either =0.05or =0.01.

(b) significant at =0.05but not at =0.01

(c) significant at =0.01but not at =0.05.

(d) significant at both =0.05and =0.01.

(e) inconclusive because we don鈥檛 know the value of 藛p .

鈥淚 can鈥檛 get through my day without coffee鈥 is a common statement from many students. Assumed benefits include keeping students awake during lectures and making them more alert for exams and tests. Students in a statistics class designed an experiment to measure memory retention with and without drinking a cup of coffee one hour before a test. This experiment took place on two different days in the same week (Monday and Wednesday). Ten students were used. Each student received no coffee or one cup of coffee, one hour before the test on a particular day. The test consisted of a series of words flashed on a screen, after which the student had to write down as many of the words as possible. On the other day, each student received a different amount of coffee (none or one cup). (a) One of the researchers suggested that all the subjects in the experiment drink no coffee before Monday鈥檚 test and one cup of coffee before Wednesday鈥檚 test. Explain to the researcher why this is a bad idea and suggest a better method of deciding when each subject receives the two treatments.

(b) The data from the experiment are provided in the table below. Set up and carry out an appropriate test to determine whether there is convincing evidence that drinking coffee improves memory.

Better barley Does drying barley seeds in a kiln increase the yield of barley? A famous experiment by William S. Gosset (who discovered the t distributions) investigated this question. Eleven pairs of adjacent plots were marked out in a large field. For each pair, regular barley seeds were planted in one plot and kiln-dried seeds were planted in the other. The following table displays the data on yield (lb/acre).

(a) How can the Random condition be satisfied in this study?

(b) Perform an appropriate test to help answer the research question. Assume that the Random condition is met. What conclusion would you draw?

A 95%confidence interval for a population mean is calculated to be (1.7,3.5). Assume that the conditions for performing inference are met. What conclusion can we draw for a test of role="math" localid="1650275427722" H0:=2versus Ha:2at the A=0.05level based on the confidence interval?

(a) None. We cannot carry out the test without the original data.

(b) None. We cannot draw a conclusion at the A=0.05level since this test is connected to the 97.5%confidence interval.

(c) None. Confidence intervals and significance tests are unrelated procedures.

(d) We would reject H0at level A=0.05.

(e) We would fail to reject H0at level A=0.05.

Does this paper give convincing evidence that the mean amount of sugar in the hindguts under these conditions is not equal to 7mg? Justify your answer.

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