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Chapter 9: Q 1.2. (page 570)

For the job satisfaction study described in Section 9.1, the hypotheses are

H0鈭�渭=0Ha:渭鈮�0

where 渭is the mean difference in job satisfaction scores (self-paced - machine-paced) in the population of assembly-line workers at the company? Data from a random sample of 18workers gave x=17andsx=60

Use Table B to find the P-value. What conclusion would you draw?

Short Answer

Expert verified

The P -value is 0.221

Step by step solution

01

Given information

Sample mean (x)=17

Sample size (n)=18

Sample standard deviation (s)=60

Test statistic (t)=1.273

02

Concept

The test statistic is computed as: t=x铃�鈭�渭sn

x = Sample mean

渭 = Population mean

n = Sample size

s = Sample standard deviation

03

Calculation

The degree of freedom is computed as:

Df=n鈭�1=18鈭�1=17

The P-value can be calculated as:

P鈭�value=2脳P(t>|1.2)=0.221

P is bigger than the significance level in this case (0.221).(0.05). The null hypothesis is rejected in this case.

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