/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.15 Run a mile During World War II, ... [FREE SOLUTION] | 91影视

91影视

Run a mile During World War II, able-bodied male undergraduates at the University of Illinois participated in required physical training. Each student ran a timed mile. Their times followed the Normal distribution with mean 7.11minutes and standard deviation 0.74minute. An SRS of 100of these students has mean time x=7.15minutes. A second SRS of size100has mean x=6.97minutes. After many SRSs, the values of the sample mean x follow the Normal distribution with mean 7.11 minutes and standard deviation0.074minute.

(a) What is the population? Describe the population distribution. (b) Describe the sampling distribution of x. How is it different from the population distribution?

Short Answer

Expert verified

a). The population distribution is a Normal distribution.

b). Average time to run a mile of 100students from the population. Smaller standard deviation.

Step by step solution

01

Part (a) Step 1: Given Information 

The values of the sample mean x follow the Normal distribution with mean 7.11 minutes and a standard deviation of 0.074 minute.

02

Part (a) Step 2: Explanation 

Individuals who are being examined make up the population.

POPULATION=12000able-bodied male undergraduates from the University of Illinois who took part in World War II physical training.

The population distribution is given as a Normal distribution with a mean of 7.11minutes and a standard deviation of 0.74minutes, corresponding to the time it takes for randomly selected individuals to run a mile.

03

Part (b) Step 1: Given Information 

The values of the sample mean x follow the Normal distribution with mean 7.11 minutes and standard deviation 0.074 minute

04

Part (b) Step 2: Explanation 

The sample mean xvalues are distributed normally, with a mean of 7.11minutes and a standard deviation of 0.074minutes.

As a result x's sample distribution is the Normal distribution, with a mean of 7.11minutes and a standard deviation of 0.074minutes.

The xsample distribution describes the average time taken by 100students from the population to run a mile.

The reduced standard deviation distinguishes it from the population distribution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Larger sample Suppose that the blood cholesterol level of all men aged 20-34follows the Normal distribution with mean =188milligrams per deciliter (mg/dl) and standard deviation =41mg/dl

(a) Choose an SRS of 100men from this population What is the sampling distribution of x?

(b) Find the probability that xestimates within 3mg/dl. (This is the probability thatxtakes a value between 185and191mg/dl.) Show your work.

(c) Choose an SRS of 1000men from this population. Now what is the probability that xfalls within3mg/dlof? show your wrok.in what sense is the large sample "better".

More on insurance An insurance company knows that in the entire population of homeowners, the mean annual loss from 铿乺e is =250and the standard deviation of the loss is =300. The distribution of losses is strongly right-skewed: many policies have 0loss, but a few have large losses. If the company sells 10,000 policies, can it safely base its rates on the assumption that its average loss will be no greater than 275? Follow the four-step process

How tall? A random sample of female college students has a mean height of 64.5 inches, which is greater than the 63-inch mean height of all adult American women.

The number of hours a light bulb burns before failing varies from bulb to bulb. The distribution of burnout times is strongly skewed to the right. The central limit theorem says that

(a) as we look at more and more bulbs, their average burnout time gets ever closer to the mean for all bulbs of this type.

(b) the average burnout time of a large number of bulbs has a distribution of the same shape (strongly skewed) as the population distribution.

(c) the average burnout time of a large number of bulbs has a distribution with a similar shape but not as extreme (skewed, but not as strongly) as the population distribution.

(d) the average burnout time of a large number of bulbs has a distribution that is close to Normal.

(e) the average burnout time of a large number of bulbs has a distribution that is exactly Normal.

Decreasing the sample size from 750to 375would multiply the standard deviation by

(a) 2.

(b) 2.

(c) 1/2.

(d) 1/2.

(e) none of these.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.