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(a) Would you be surprised if none of the candies were orange? Compute an appropriate probability to support your answer.

(b) How surprising would it be to get 5or more orange candies? Compute an appropriate probability to support your answer

Short Answer

Expert verified

(a)The probability is0.1678

(b) The probability is0.0104

Step by step solution

01

Part (a) Step 1: Given information

Given in the question that, according to the Mars candy company, 20%of its plain M&M鈥檚 candies are orange. Assume that the company鈥檚 claim is true. Suppose that you reach into a large bag of plain M&M鈥檚 (without looking) and pull out 8candies. LetX = the number of orange candies you get.

02

Part (a) Step 2: Explanation

Given:

Probability of success (p)=20%=0.20.

Number of trials (n)=8

Calculation:

Here, Xis a random variable that indicates the number of orange candies.

The probability of selecting 0orange candies is:

P(X=0)=8C0(0.20)0(10.20)80

=0.1678

Thus, the probability is0.1678.

Here, probability is above5%. Thus, the event is not surprising.

03

Part (b) Step 1: Given information

Given in the question that, According to the Mars candy company, 20% of its plain M&M鈥檚 candies are orange. Assume that the company鈥檚 claim is true. Suppose that you reach into a large bag of plain M&M鈥檚 (without looking) and pull out 8 candies. Let X = the number of orange candies you get.

04

Part (b) Step 2: Explanation

The probability of selecting more than 5orange candies is calculated as:

P(X5)=1P(X<5)

=1[P(X=0)+P(X=1)+.+P(X=4)]

=0.0104

Thus, the probability is 0.0104.

Here, probability is below 5%. Thus, the event is surprising to happen.

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