/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 82 Lie detectors A federal report f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Lie detectors A federal report finds that lie detector tests given to truthful persons have probability about 0.2 of suggesting that the person is deceptive. A company asks 12job applicants about thefts from
previous employers, using a lie detector to assess their truthfulness. Suppose that all 12 answer truthfully. Let X=the number of people who the lie detector says are being deceptive.
(a) Find and interpret μX.
(b) Find and interpret σX.

Short Answer

Expert verified

(a) The interpret μX is 2.4.

(b) The interpret σXis 1.3856.

Step by step solution

01

Part (a) Step 1: Given information 

A company asks 12job applicants about thefts from previous employers, using a lie detector to assess their truthfulness .

02

Part (a) Step 2: Explanation 

Let, n=12and p=0.20

The mean of the sample size nand the probability is:

μx=n×p=12(0.20)=2.4

According to the lie detector, on average of 2.4people are deceptive.

03

Part (b) Step 1: Given information 

LetX= the number of people who the lie detector says are being deceptive.

04

Part (b) Step 2: Explanation 

Let, n=12, and p=0.20.

The standard deviation of the sample size nand the probability p:

σx=(n×p)(1-p)

=12(0.20)(1-0.20)

=1.3856

This means that on average, the number of persons who the lie detector claims are lying varies by a factor of two. 1.3856.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

To introduce her class to binomial distributions, Mrs. Desai gives a 10-item, multiple-choice quiz. The catch is, that students must simply guess an answer (A through E) for each question. Mrs. Desai uses her computer's random number generator to produce the answer key so that each possible answer has an equal chance to be chosen. Patti is one of the students in this class.

Let X=the number of Patti's correct guesses.

To get a passing score on the quiz, a student must guess correctly at least 6times. Would you be surprised if Patti earned a passing score? Compute an appropriate probability to support your answer.

Fire insurance Suppose a homeowner spends \(300for a home insurance policy that will pay out \)200,000if the home is destroyed by fire. Let Y=the profit made by the company on a single policy. From previous data, the probability that a home in this area will be destroyed by fire is 0.0002.

(a) Make a table that shows the probability distribution of Y.

(b) Compute the expected value of Y. Explain what this result means for the insurance company

Toss 4times Suppose you toss a fair coin 4times. Let X=the number of heads you get.

(a) Find the probability distribution ofX.

(b) Make a histogram of the probability distribution. Describe what you see.

(c) Find P(X≤3) and interpret the result.

Suppose you roll a pair of fair, six-sided dice until you get doubles. Let T=the number of rolls it takes.

Find P(T=3). Interpret this result in context.

A test for extrasensory perception (ESP) involves asking a person to tell which of 5shapes—a circle, star, triangle, diamond, or heart—appears on a hidden computer screen. On each trial, the computer is equally likely to select any of the 5shapes. Suppose researchers are testing a person who does not have ESP and so is just guessing on each trial. What is the probability that the person guesses the first 4shapes incorrectly but gets the fifth correct?

a). 1/5

b). 454

c). 45415

d). 5145415

e).4/5

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.