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Based on the analysis in Exercise 41, the ferry company decides to increase the cost of a trip to $6. We can calculate the company’s profit Yon a randomly selected trip from the number of cars X. Find the mean and standard deviation ofY. Show your work.

Short Answer

Expert verified

The mean and standard deviation are

μY=3.22

σY=7.74

Step by step solution

01

Given Information

Given in the question that

μX=3.87

σX=1.29

02

Explanation

The earnings per car Xis $6and the costs is $20:

Y=6X-20

Properties mean and standard deviation:

μaX+b=aμX+b

σaX+b=aσX

Then we obtain for Y=6X-20:

localid="1649908128618" μY=μ6X-20=6μX-20=6(3.87)-20=3.22

localid="1649908143820" σY=σ6X-20=6σX=6(1.29)=7.74

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Most popular questions from this chapter

25. Did you vote? A sample survey contacted an SRS of 663 registered voters in Oregon shortly after an election and asked respondents whether they had voted. Voter records show that 56%of registered voters had actually voted. We will see later that in repeated random samples of size 663, the proportion in the sample who voted (call this proportion V) will vary according to the Normal distribution with mean μ=0.56 and standard deviation σ=0.019.
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