/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 22 22. Random numbers Let Y聽be a n... [FREE SOLUTION] | 91影视

91影视

22. Random numbers Let Ybe a number between0 and 1 produced by a random number generator. Assuming that the random variable Y has a uniform distribution, find the following probabilities:
(a) P(Y0.4)
(b) role="math" localid="1649593908596" P(Y<0.4)
(c) role="math" localid="1649593922659" P(0.1<Y0.15or0.77Y<0.88

Short Answer

Expert verified

(a) The probability for P(Y0.4)is 0.40

(b) The probability for P(Y<0.4 is 0.40

(c) The probability for role="math" localid="1649594539701" P(0.1<Y0.15or0.77Y<0.88)is 0.16.

Step by step solution

01

Part (a) Step 1: Given information 

To find the probability for P(Y0.4).

02

Part (a) Step 2: Explanation 

The variableY is following the uniform distribution.
The probability forP(Y0.4)can be determined as:
P(Y0.4)=(0.4-0)1=0.40

03

Part (b) Step 1: Given information

To find the probability for P(Y<0.4)

04

Part (c) Step 2: Explanation 

The variableY is following the uniform distribution.
The probability forP(Y<0.4) can be determined as:
P(Y<0.4)=(0.4-0)1=0.40

05

Part (c) Step 1: Given information 

To find the probability for P(0.1<Y0.15or0.77Y<0.88).

06

Part (c) Step 2: Explanation 

The probability forP(0.1<Y0.15or0.77Y<0.88) can be determined as:
P(0.1<Y0.15)=(0.15-0.1)1=0.05
P(0.77Y0.88)=(0.88-0.77)1=0.11

Then,

P(0.1<Y0.15or0.77Y0.88)=0.05+0.11=0.16

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Toss 4times Suppose you toss a fair coin 4times. Let X=the number of heads you get.

(a) Find the probability distribution ofX.

(b) Make a histogram of the probability distribution. Describe what you see.

(c) Find P(X3) and interpret the result.

Ten lines in the table contain 400digits. The count of 0s in these lines is approximately Normal with

(a) mean 40; standard deviation 36.

(b) mean 40; standard deviation19.

(c) mean 40; standard deviation 6.

(d) mean 36; standard deviation6.

(e) mean 10; standard deviation 19.

A large auto dealership keeps track of sales made during each hour of the day. Let X= the number of cars sold during the 铿乺st hour of business on a randomly selected Friday. Based on previous records, the probability distribution of Xis as follows:

The random variable Xhas mean X=1.1and standard deviation X=0.943.

Suppose the dealership鈥檚 manager receives a 500bonus from the company for each car sold. Let Y = the bonus received from car sales during the 铿乺st hour on a randomly selected Friday. Find the mean and standard deviation of Y.

49. Checking independence In which of the following games of chance would you be willing to assume independence of Xandlocalid="1649903939419" Y in making a probability model? Explain your answer in each case.
(a) In blackjack, you are dealt two cards and examine the total points localid="1649903945891" Xon the cards (face cards count localid="1649903950298" 10points). You can choose to be dealt another card and compete based on the total pointslocalid="1649903956461" Y on all three cards.
(b) In craps, the betting is based on successive rolls of two dice. localid="1649903966379" Xis the sum of the faces on the first roll, and localid="1649903971075" Yis the sum of the faces on the next roll.

A large auto dealership keeps track of sales and leases agreements made during each hour of the day. Let X= the number of cars sold and Y= the number of cars leased during the 铿乺st hour of business on a randomly selected Friday. Based on previous records, the probability distributions of Xand Yare as follows:

顿别铿乶别 D=X-Y.

The dealership鈥檚 manager receives a 500bonus for each car sold and a300 bonus for each car leased. Find the mean and standard deviation of the difference in the manager鈥檚 bonus for cars sold and leased. Show your work.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.