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In the most recent year, the following is the distribution of adjusted go income reported on individual federal income tax returns:

For mutually exclusive events, use the following addition rule:

$P(AorB)=P\left(A\right)+P\left(B\right)$

For mutually exclusive events, use the addition rule: $P(AorB)=P\left(A\right)+P\left(B\right)$

Fill in the blanks with the corresponding probabilities:

$P(income>\$50000)=P(>50)$

As a result, the likelihood of a random selection returning is

$P(income>\$50000)=0.321$

$P(income>\$50000)=0.321$

$P(income鈮�\$50000and鈮�100,000)=P(>100,000)$

condition probability: $P(A/B)=P(AandB)/P\left(B\right)$

$P(鈮�\$100,000/鈮�\$50,000)=\frac{P(鈮�\$100,000and鈮�\$50,000)}{P(鈮�\$50,000)}$

$=\frac{0.106}{0.321}鈮�0.3302=33.2\%$

As a result, the conditional probability of earning at least $\$100,000$ is

$P(鈮�\$100,000/鈮�\$50,000)=33.2\%$