91影视

The likelihood of English, $P\left(E\right)=0.63$

The likelihood of French, $P\left(F\right)=0.22$

The likelihood of Asian/Pacific, $P\left(\raisebox{1ex}{$A$}\!\left/ \!\raisebox{-1ex}{$P$}\right.\right)=0.06$

An event is a subset of an experiment's total number of outcomes. The ratio of the number of elements in an event to the number of total outcomes is the probability of that occurrence.

The following are the conditions for probability distribution: 1) The probabilities must be

2)The sum of all probability should equal $1$. Using condition $2$, $$\begin{gathered} 0.63+0.22+0.06+P\left(other\right)=1 \\ P\left(Other\right)=1-0.91=0.09 \end{gathered}$$

$P(A^c)=1-P\left(A\right)$Using the complementary probability formula,$P(notEnglish)=1-P\left(English\right)=1-0.63=0.37$

$P(AorB)=P\left(A\right)+P\left(B\right)$The likelihood that a Canadian's mother tongue language is neither English or French denotes the Asian/Pacific or Other language. By applying a formula,$P(Asian/PacificorOther)=P(Asian/Pacific)+P\left(Other\right)P(Asian/PacificorOther)=0.06+0.09=0.15$