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Ten percent of U.S. households contain 5or more people. You want to simulate choosing a household at random and recording whether or not it contains 5or

more people. Which of these are correct assignments of digits for this simulation? (a) Odd = Yes (5or more people); Even = No (not 5or more people)

(b) 0= Yes; 1,2,3,4,5,6,7,8,9= No

(c) 5= Yes; 0,1,2,3,4,6,7,8,9= No

(d) All three are correct.

(e) Choices (b) and (c) are correct, but (a) is not.

Short Answer

Expert verified

The choices (b) and (c) are correct, but (a) is not.

Step by step solution

01

Step 1. Given Information    

percent of homes in the United States with 5or more individuals = 10% For this simulation, we must determine the correct digit assignments:

02

Step 2. Concept Used  

We can't foresee the outcomes of a chance process, yet they have a regular distribution over a large number of repetitions. According to the law of large numbers, the fraction of times a specific event occurs in numerous repetitions approaches a single number. The likelihood of a chance outcome is its long-run relative frequency. A probability is a number between 0(never happens) and 1(happens frequently) (always occurs).

03

Step 3. Explanation   

We will check each of the given options.

a) The 5out of the 10 digits result in 5or more people, resulting in a probability of 50%instead of 10%Hence, it is incorrect.

b)The 1out of the 10digits result in 5or more people, resulting in a probability of 10%Hence, it is correct.

(c) The 1out of the 10digits result in 5or more people, resulting in a probability of 10%Hence, it is correct.

(d) Incorrect as we already know (a) is incorrect. (e) correct because (b) and (c) are correct and (a) is incorrect.

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