91影视

We have been given that the data of the random samples of participants (men and women) participated in mud wrestling event. These samples were collected when one male and six female students complained of rashes after participating in a mud-wrestling event. Data is depicted in the tables given in question.

We need to find the cell that contributes most to the chi-square statistics.

Firstly, find the difference between an observed frequency and an expected frequency for men and women:

Women who developed a rash:

$\left|Observed-Expected\right|=\left|12-7.78\right|=4.22$

Women who did not develop a rash:

$\left|Observed-Expected\right|=\left|12-16.22\right|=4.22$

Men who developed a rash:

$\left|Observed-Expected\right|=\left|12-16.22\right|=4.22$

Men who did not develop a rash:

$\left|Observed-Expected\right|=\left|38-33.78\right|=4.22$

We have observed that all the four cells have the same difference of observed and expected frequency. So, that's why, the cell which has the lowest expected value contributed the most.

The lowest expected value is for women who developed a rash i.e. $7.78$.

So, the women who developed a rash contribute the most to the chi-square statistic.