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A score in the ${95}^{th}$ percentile is a figure on a scale of $100$ that represents the percentage of a distribution that is equal to or below it.

The graph below shows the amount spent by $50$ consecutive supermarket shoppers at a retailer in a cumulative relative frequency graph.

Based on the cumulative relative frequency graph above, we are meant to calculate the Inter-Quartile range of the amount spent by $50$ consecutive grocery shoppers at a store. The following is how the inter-quartile range is defined: $IQR=Q3−Q1$

The ${25}^{th}$ percentile belongs to $Q1$, and the ${75}^{th}$ percentile relates to $Q3$.

The following is the procedure for determining the quartiles:

Step 1: Determine the place on the ogive where the line intersects the ogive by drawing a horizontal line from the value $25$ on the vertical axis.

Step 2: From this point, draw a vertical line to the horizontal axis. At around $\$19$, the line intersects the axis.

As a result, the expected cost Q1 is $\$19$.

Step 3: Determine the location on the ogive where the line intersects the ogive by drawing a horizontal line from the value $75$ on the vertical axis.

Step 4: Connect this point to the horizontal axis with a vertical line. Around $\$46$is where the line crosses the axis. As a result, the estimated cost $Q3$is $\$46$. The technique is depicted in the graph below: As a result, the Inter-Quartile Range is calculated as this: $IQR=Q_{3-}{Q}_1=46-19=27$. $IQR=Q_3-Q_1=46$$IQR=Q_1=46$$IQR=Q_1=46$$IQ$As a result, the Inter-Quartile range of the amount spent at a store by $50$consecutive food buyers is $\$27$.

Therefore, the Inter-Quartile range is $\$27$

We can observe from the graph above that the consumer who spent $\$19.50$is just above the 25th percentile. As a result, $\$19.50$is roughly in the ${26}^{th}$percentile. Hence, $\$19.50$is at about the ${26}^{th}$ percentile.

The cumulative frequencies corresponding to different mid values can be found in the cumulative graph above. Cumulative frequencies obtained from the cumulative graph are $5,25,55,62,80,87,8890,96,98,$which correspond to mid values$10,20,30,40,50,60,70,80,90,100.$The comparable frequencies are $5,20,30,7,18,7,1,2,6,2$ and $5,20,30,7,18,7,1,2,6,2$ respectively. We create a histogram for the given data using frequencies. The following is the graph that was created: The data about the amount spent by $50$ successive grocery shoppers at a store is stretched towards the right side of the histogram. As a result, we may claim that the data presented above is skewed to the right. Therefore, the histogram is drawn.