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Scores on the ACT college entrance exam follow a bell-shaped distribution with a mean 18 and a standard deviation 6. Wayne’s standardized score on the ACT was −0.7 What was Wayne’s actual ACT score? (a)4.2(b)−4.2(c)13.8(d)17.3(e)22.2

Short Answer

Expert verified

The correct option is (c).

Step by step solution

01

Step 1. Given

The average population (μ)=18

The standard deviation of the population (σ)=6

A score that is standardized (z)=-0.7

02

Step 2. Concept

The z score is calculated using the following formula: z=X−μ/σ

03

Step 3. Calculation

Consider that X reflects Wayne's real ACT score, which follows a normal distribution with a mean of 18and a standard deviation of6.

Wayne's real ACT score is determined as follows:

z=X−μσ

−0.7=X−186

−4.2+18=X

X=13.8

Hence, the correct option is (c)13.8

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