91影视

To construct the graph, the proportions are computed as:

The graph could be constructed:

From the above figure, it is clear that most of the people in each category are not supporting the law and this proportion seems to be highest in the group of "Some college".

The appropriate null and alternative hypotheses for the provided test could be written as:

$H_0$: Two variables are independent

$H_a$: Two variables are dependent

The expected count is computed as:

The test statistic is:

$$\begin{gathered} {蠂}^2=鈭�\frac{(O-E{)}^2}{E} \\ =\frac{(58-46.9409{)}^2}{46.9409}+\frac{(58-69.0591{)}^2}{69.0591}+鈥�鈥�.+\frac{(99-104.7794{)}^2}{104.7794} \\ =8.525 \end{gathered}$$

The degree of freedom is calculated as:

$$\begin{gathered} Degreeoffreedom=(Numberofrows-1)(Numberofcolumn-1) \\ =(5-1)(2-1) \\ =4 \end{gathered}$$

The $p$-value using chi-square table at $4$degree of freedom is $0.074133$.

The p -value is above significance level. The null hypothesis does not get rejected. Thus, there is sufficient evidence to conclude that there is not an association between two variables.