/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 46 The General Social Survey asked ... [FREE SOLUTION] | 91影视

91影视

The General Social Survey asked a random sample of adults their opinion about whether astrology is very scientific, sort of scientific, or not at all scientific. Here is a two-way table of counts for people in the sample who had three levels of higher education:

(a) Make a bar graph that compares opinions about astrology for the three education categories. Describe what you see.

(b) Minitab output for a chi-square test using these data is shown below. Carry out the test. What conclusion do you draw?

Short Answer

Expert verified

(a) The higher the degree of the subjects, the more likely that they think that astrology is not at all scientific.

(b) There is sufficient evidence that there is an association between the variables.

Step by step solution

01

Part (a) Step 1: Given information

The given data is

02

Part (a) Step 2: Explanation

The proportions in each group is the number of subjects divided by the column total:

Create a histogram

The width of each bar is equal and the height is equal to the proportion.

03

Part (b) Step 1: Given information

The given data is

04

Part (b) Step 2: Explanation

The null hypothesis states that there is no association between the variables:

H0: There is no association between the variables

The alternative hypothesis states that there is an association between the variables:

Ha: There is an association between the variables

By using the test of chi-squater, we obtained that:

x2=10.582

Let's find the degree of freedom:

=(31)(21)=21=2

The P-value is given in the output as:

P=0.005

If the P-value is smaller than the significance level, reject the null hypothesis:

P<0.05RejectH0

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A company claims that each batch of its deluxe mixed nuts contains 52%cashews, 27%almonds, 13%macadamia nuts, and 8%brazil nuts. To test this claim, a quality control inspector takes a random sample of 150nuts from the latest batch. The one-way table below displays the sample data.

(a) State appropriate hypotheses for performing a test of the company鈥檚 claim.

(b) Calculate the expected counts for each type of nut. Show your work

Inference recap (8.1to11.2)In each of the following settings, say which inference procedure from Chapters 8,9,10,or11you would use. Be specific. For example, you might say 鈥渢wo-sample z test for the difference between two proportions.鈥 You do not need to carry out any procedures.

(a) Is there a relationship between attendance at religious services and alcohol consumption? A random sample of 1000adults was asked whether they regularly attend religious services and whether they drink alcohol daily.

(b) Separate random samples of 75college students and 75 high school students were asked how much time, on average, they spend watching television each week. We want to estimate the difference in the average amount of TV watched by high school and college students.

Calculate the chi-square statistic for Joey鈥檚 sample. Show your work

Sorry, no chi-square (11.1) Explain why it would not be appropriate to perform a chi-square goodness-of-fit test in this setting.

Seagulls by the seashore Do seagulls show a preference for where they land? To answer this question, biologists conducted a study in an enclosed outdoor space with a piece of shore whose area was made up of 56% sand, 29% mud, and 15% rocks. The biologists chose 200seagulls at random. Each seagull was released into the outdoor space on its own and observed until it landed somewhere on the piece of shore. In all, 128seagulls landed on the sand, role="math" localid="1650465230449" 61landed in the mud, and role="math" localid="1650465221489" 11landed on the rocks. Carry out a chi-square goodness-of-铿乼 test. What do you conclude?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.