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Chapter 8: Q.3.3 (page 511)

Construct a 95% confidence interval forM. Show your method

Short Answer

Expert verified

The obtained confidence interval is (22.338,29.962)

Step by step solution

01

Given information

Given in the question that, Biologists studying the healing of skin wounds measured the rate at which new cells closed a cut made in the skin of an anesthetized newt. Here are data from a random sample of 18newts, measured in micrometers (millionths of a meter) per hour:

20292734402228143526351230231811222333

02

Explanation

The given dataset is

29
27
34
40
22
28
14
35
36
35
12
30
23
18
11
2223
33

The formula to compute the confidence interval is:

x炉-ta2脳sn<渭<x炉+ta2脳sn

The output obtained using Ti-83calculator is:

Thus, the obtained confidence interval is(22.338,29.962).

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Most popular questions from this chapter

Interpret the confidence level.

You have an SRS of 23 observations from a Normally distributed population. What critical value would you use to obtain a 98% confidence interval for the mean M of the population if S is unknown?

(a) 2.508

(b) 2.500

(c) 2.326

(d) 2.183

(e) 2.177

An online poll posed the following question:

It is now possible for school students to log on to Internet sites and download homework. Everything from book reports to doctoral dissertations can be downloaded free or for a fee. Do you believe that giving a student who is caught plagiarizing an F for their assignment is the right punishment?

Of the 20,125people who responded, 14,793clicked 鈥淵es.鈥� That鈥檚 73.5%of the sample. Based on this sample, a 95%confidence interval for the percent of the population who would say 鈥淵es鈥� is 73.5% 卤0.61. Which of the three inference conditions is violated? Why is this confidence interval worthless?

You want to compute a 90%confidence interval for the mean of a population with unknown population standard deviation. The sample size is 30. The value of role="math" localid="1649226392559" tyou would use for this interval is

(a)1.645(b).1.699(c)1.697

(d) 1.96(e) 2.045

Prayer in school A New York Times/CBS News Poll asked the question, 鈥淒o you favor an amendment to the Constitution that would permit organized prayer in public schools?鈥� Sixty-six percent of the sample answered 鈥淵es.鈥� The article describing the poll says that it 鈥渋s based on telephone interviews conducted from Sept. 13 to Sept. 18 with 1664adults around the United States, excluding Alaska and Hawaii. . . . The telephone numbers were formed by random digits, thus permitting access to both listed and unlisted residential numbers.鈥� The article gives the margin of error for a 95%confidence level as 3percentage points.

(a) Explain what the margin of error means to someone who knows little statistics.

(b) State and interpret the 95% confidence interval.

(c) Interpret the confidence level.
See all solutions

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