91影视

Given in the question that, Use Table B to find the critical value t* that you would use for a confidence interval for a population mean M in each of the following situations. A 98% confidence interval based on$n=22$observations.

Given:

Confidence level $=98\%$

Sample size $\left(n\right)=22$

The level of significance is:

Level of significance

Level of significance$=1-$Confidence level

$=1-0.98$

$=0.02$

The degree of freedom is$22-1=21$

The critical value using standard normal table is calculated as:

localid="1649870225365" $t_{a/2df}=t_{0.02/2,21}$

$=2.518$

The critical value is$2.518$

Given in the question that, Use Table B to find the critical value t* that you would use for a confidence interval for a population mean M in each of the following situations. If possible, check your answer with technology. A $90\%$confidence interval from an SRS of$10$ observations.

Given:

Confidence level $=90\%$

Sample size $\left(n\right)=10$

The level of significance is:

Level of significance$=1-$Confidence level

$=1-0.90$

$=0.10$

The degree of freedom is $10-1=9$

The critical value using standard normal table is calculated as:

$t_{a/2df}=t_{0.10/2,9}$

$=1.833$

The critical value is$1.833$.

Given in the question that, Use Table B to find the critical value t* that you would use for a confidence interval for a population mean M in each of the following situations. If possible, check your answer with technology. (c) A$95\%$confidence interval from a sample of size$7$.

Given:

Confidence level $=95\%$

Sample size $\left(n\right)=7$

The level of significance is:

Level of significance$=1-$Confidence level

$=1-0.95$

$=0.05$

The degree of freedom is$7-1=6$

The critical value using standard normal table is calculated as:

$t_{a/22d}=t_{0.05/2,6}$

$=2.447$

The critical value is$2.447$