/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.2 聽The weights (in pounds) of thr... [FREE SOLUTION] | 91影视

91影视

The weights (in pounds) of three adult males are 160,215and195. The standard error of the mean of these three weights is

(a) 190

(b) 27.84

(c) 22.73

(d) 16.07

(e)13.13

Short Answer

Expert verified

(e) The standard error of mean is13.13

Step by step solution

01

Step-1 Given Information

Given In the question that , The weights of three adult males are 160,215,and195we have to find the correct option.

02

Step-2 Explanation

The formula to compute the standard error of mean is:

StandarderrorMean=n

The values of mean and standard deviation using Ti-83 calculator could be calculated as:

From the above output, the standard deviation =22.73and sample size =3

The standard error of the mean is calculated as follows:

StandarderrorMean=n

localid="1649222387632" =22.733

=13.13

Hence, the correct option is (e)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How heavy a load (pounds) is needed to pull apart pieces of Douglas fir 4inches long and 1.5inches square? A random sample of 20similar pieces of Douglas fir from a large batch was selected for a science class. The Fathom boxplot below shows the class鈥檚 data. Explain why it would not be wise to use a one-sample t interval to estimate the population mean.

The AP Statistics class in Exercise 1 also asked an SRS of 20 boys at their school how many shoes they have. A 95% confidence interval for the difference in the population means (girls 鈥 boys) is 10.9 to 26.5. Interpret the confidence interval and the confidence level.

57. Critical values What critical value t* from Table B would you use for a confidence interval for the population mean in each of the following situations?
(a) A 95%confidence interval based on  n=10 observations.
(b) A 99%confidence interval from an SRS of 20 observations.

School vouchers A national opinion poll found that 44% of all American adults agree that parents should be given vouchers that are good for education at any public or private school of their choice. The result was based on a small sample.

(a) How large an SRS is required to obtain a margin of error of 0.03(that is, 3%) in a 99% con铿乨ence interval? Answer this question using the previous poll鈥檚 result as the guessed value for p.

(b) Answer the question in part (a) again, but this time use the conservative guess p=0.5. By how much do the two sample sizes differ?

An online poll posed the following question:

It is now possible for school students to log on to Internet sites and download homework. Everything from book reports to doctoral dissertations can be downloaded free or for a fee. Do you believe that giving a student who is caught plagiarizing an F for their assignment is the right punishment?

Of the 20,125people who responded, 14,793clicked 鈥淵es.鈥 That鈥檚 73.5%of the sample. Based on this sample, a 95%confidence interval for the percent of the population who would say 鈥淵es鈥 is 73.5% 0.61. Which of the three inference conditions is violated? Why is this confidence interval worthless?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.