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Chapter 8: Q. 16 (page 483)

Many teens have posted profiles on sites such as Facebook and My Space. A sample survey asked random samples of teens with online profiles if they included false information in their profiles. Of 170younger teens (ages 12to 14) polled, 117said 鈥淵es.鈥� Of 317older teens (ages 15to 17) polled, 152 said 鈥淵es.鈥�6 A 95% confidence interval for the difference in the population proportions (younger teens 鈥� older teens) is 0.120 to 0.297. Interpret the confidence interval and the confidence level

Short Answer

Expert verified

Interpretation confidence level: The confidence interval contains the true difference in population proportions, on average, in 95%of all samples.

Step by step solution

01

Given Information

A sample survey asked random samples of teens with online profiles if they included false information in their profiles.

02

Explanation

The given 95%confidence interval for the difference in population proportions is 0.120to 0.297.

Interpretation: We are 95%confidence that the difference in the population proportions between younger teens and older teens is between 0.120and 0.297.

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Most popular questions from this chapter

Refer to Exercise 12. As Gallup indicates, the 3percentage point margin of error for this poll includes only sampling variability (what they call 鈥渟ampling error鈥�). What other potential sources of error (Gallup calls these 鈥渘on-sampling errors鈥�) could affect the accuracy of the59% estimate?

The weights (in pounds) of three adult males are 160,215and195. The standard error of the mean of these three weights is

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15.813.615.619.122.415.622.517.219.422.6
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(a) How large a sample must you test to estimate the proportion of PTC tasters within 0.04with 90% con铿乨ence? Answer this question using the 75% estimate as to the guessed value for p鈭�.

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