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Find the probability that p1^-p2^is less than or equal to 0.02. Show your work.

Short Answer

Expert verified

The required probability is 0.2061.

Step by step solution

01

Given Information

Meanp^1-p^2=-0.10.

Standard deviation p^1-p^2=0.097.

02

Explanation

The probability that p^1-p^2is less than or equal to -0.02can be computed as:

localid="1650444373982" Pp^1-p^2-0.02=Pp^1-p^2-p1-p2p^1-p^2-0.02-p1-p2p^1-p^2=PZ0.02(0.1)0.097=P(Z>0.82)=0.2061

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