91影视

The given data is

The given values are

${\overline{x}}_1=70.37$

${\overline{x}}_2=68.45$

$s_1=6.10$

$s_2=9.04$

$n_1=10$

$n_2=8$

Determine the hypothesis

$H_0:{渭}_1={渭}_2$

$H_a:{渭}_1鈮�{渭}_2$

Find the test statistic

localid="1650519634974" $$\begin{gathered} t=\frac{{\stackrel{炉}{x}}_1-{\stackrel{炉}{x}}_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}} \\ =\frac{70.37-68.45}{\sqrt{\frac{6.{10}^2}{10}+\frac{9.{04}^2}{8}}} \\ 鈮�0.5143 \end{gathered}$$.

The given data is

From the given data in part (a)

Find the hypothesis

$H_0:{渭}_1={渭}_2$

$H_a:{渭}_1鈮�{渭}_2$

Find the test statistic

localid="1650519670442" $$\begin{gathered} t=\frac{{\stackrel{炉}{x}}_1-{\stackrel{炉}{x}}_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}} \\ =\frac{70.37-68.45}{\sqrt{\frac{6.{10}^2}{10}+\frac{9.{04}^2}{8}}} \\ 鈮�0.5143 \end{gathered}$$

Find the degree of freedom

localid="1650519689707" $$\begin{gathered} df=\min \left(n_1-1,n_2-1\right) \\ =\min (10-1,8-1) \\ =7 \end{gathered}$$

The P-value is the chance of getting the test statistic's result or a number that is more severe. The P-value is the number (or interval) in Table B's column title that corresponds to the t-value in the row $df=7$

$P>2脳0.25=0.50$

If the P-value is less than or equal to the significance level, then the null hypothesis is rejected:

$P>0.05鈬�Failtoreject{H}_0$

There is no sufficient evidence to support the claim of a difference.

The given data is

Determine the degrees of freedom using the conservative approach:

$$\begin{gathered} df=\min \left(n_1-1,n_2-1\right) \\ =\min (10-1,8-1) \\ =7 \end{gathered}$$

We note that the degrees of freedom is less than the degrees of freedom in the output of$11.8$

A lower degree of freedom leads to a higher P-value.