/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 In Exercises 1 to 4, determine t... [FREE SOLUTION] | 91影视

91影视

In Exercises 1 to 4, determine the point estimator you would use and calculate the value of the point estimate. Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this question to an SRS of 172 undergraduates at a large university: 鈥淵ou witness two students cheating on a quiz. Do you go to the professor?鈥 Only 19 answered 鈥淵es.鈥3

Short Answer

Expert verified
The point estimator is the sample proportion, \( \hat{p} \approx 0.1105 \).

Step by step solution

01

Identify the Point Estimator

The point estimator used in this scenario is the sample proportion \( \hat{p} \). The sample proportion estimates the proportion of a population who are willing to report cheating.
02

Calculate the Sample Proportion

To find \( \hat{p} \), use the formula: \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of successes (students answering "Yes") and \( n \) is the total number of observations. Here, \( x = 19 \) and \( n = 172 \). Calculate \( \hat{p} = \frac{19}{172} \approx 0.1105 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Point Estimators
A point estimator is a statistic used to estimate a population parameter. It's like an educated guess based on sample data. When you're trying to understand something about a whole group, you often can't measure everyone, so you take a smaller sample. The point estimator helps use this sample to make conclusions about the whole group. In statistics, common point estimators include:
  • Sample mean (for estimating the population mean)
  • Sample proportion (for estimating the population proportion)
  • Sample variance (for estimating the population variance)
In our scenario, the point estimator is the sample proportion because we are trying to estimate how many people in a population would report cheating. Understanding point estimators is crucial as they provide the foundation for estimating parameters across various statistical analyses.
Explaining Sample Proportion
The sample proportion is the ratio of the number of favorable outcomes in a sample to the total number of observations in that sample. It is expressed as \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of successes (favorable outcomes) and \( n \) is the number of trials or observations.In our example, students who answered 'Yes' are considered successes. So, our sample proportion is calculated by dividing the 19 'Yes' answers by the total 172 students surveyed. The formula becomes: \( \hat{p} = \frac{19}{172} = 0.1105 \) This result of \( 0.1105 \) provides an estimate of the proportion of students at the university willing to report cheating.
Simple Random Sample (SRS) Demystified
A Simple Random Sample (SRS) is a key method in sampling where every member of a population has an equal chance of being chosen. This method reduces bias, ensuring that the sample accurately reflects the population. Imagine pulling names out of a hat where each name has an equal chance of being picked. That's what SRS aims to achieve. SRS is important because:
  • It allows for unbiased representation of the population.
  • It simplifies the process for inferential statistics, making it easier to apply results from samples to larger populations.
In the context of our example, by using an SRS of 172 university students, we assume that every student had an equal chance of being surveyed about their willingness to report cheating. This helps ensure that our results are as unbiased as possible.
Population Proportion Estimation
Population proportion estimation is a process used to infer the proportion of a certain characteristic within a larger group. The sample proportion serves as an estimate of the true population proportion.When estimating population proportion, it's essential to consider a few elements:
  • The sample size must be large enough to reflect the population accurately.
  • The sample should be a representative group, typically achieved through an SRS.
Returning to our example, though we determined the sample proportion of \( 0.1105 \), this is used to estimate the actual proportion of all university students who would report cheating.While our sample result provides a good estimate, population proportion estimation inherently comes with some level of uncertainty. However, by following proper sampling procedures, this uncertainty can be minimized, leading to more accurate generalizations from our sample to the population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this question to an SRS of 172 undergraduates at a large university: 鈥淵ou witness two students cheating on a quiz. Do you go to the professor? Only 19 answered "Yes." (a) Identify the population and parameter of interest. (b) Check conditions for constructing a confidence interval for the parameter. (c) Construct a 99% confidence interval for p. Show your method. (d) Interpret the interval in context.

Conditions Explain briefly why each of the three conditions鈥擱andom, Normal, and Independent鈥攊s important when constructing a confidence interval.

School vouchers A national opinion poll found that 44% of all American adults agree that parents should be given vouchers that are good for education at any public or private school of their choice. The result was based on a small sample. (a) How large an SRS is required to obtain a margin of error of 0.03 (that is, \(\pm 3 \%\) ) in a 99\(\%\) confidence interval? Answer this question using the previous poll's result as the guessed value for \(\hat{p}\) . (b) Answer the question in part (a) again, but this time use the conservative guess \(\hat{p}=0.5 .\) By how much do the two sample sizes differ?

Multiple choice: Select the best answer for Exercises 75 to 78. You have an SRS of 23 observations from a Normally distributed population. What critical value would you use to obtain a 98% confidence interval for the mean M of the population if S is unknown? (a) 2.508 (c) 2.326 (e) 2.177 (b) 2.500 (d) 2.183

Multiple choice: Select the best answer for Exercises 21 to 24. A polling organization announces that the proportion of American voters who favor congressional term limits is 64%, with a 95% confidence margin of error of 3%. If the opinion poll had announced the margin of error for 80% confidence rather than 95% confidence, this margin of error would be (a) 3%, because the same sample is used. (b) less than 3%, because we require less confidence. (c) less than 3%, because the sample size is smaller. (d) greater than 3%, because we require less confidence. (e) greater than 3%, because the sample size is smaller.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.