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Run a mile During World War II, \(12,000\) able bodied male undergraduates at the University of Illinois participated in required physical training. Each student ran a timed mile. Their times followed the Normal distribution with mean 7.11 minutes and standard deviation 0.74 minute. An SRS of 100 of these students has mean time \(\overline{x}=7.15\) minutes. A second SRS of size 100 has mean \(\overline{x}=6.97\) minutes. After many SRSs, the values of the sample mean \(\overline{x}\) follow the Normal distribution with mean \(7.11 \mathrm{minutes}-\) and standard deviation 0.074 minute. (a) What is the population? Describe the population distribution. (b) Describe the sampling distribution of \(\overline{x} .\) How is it different from the population distribution?

Short Answer

Expert verified
(a) Population: 12,000 male undergraduates; Population Distribution: Normal, mean 7.11 min, SD 0.74 min. (b) Sampling Distribution: Normal, mean 7.11 min, SD 0.074 min; it has less variability than population distribution.

Step by step solution

01

Identify the Population

The population refers to all individuals from which samples are drawn. In this case, the population includes all 12,000 able-bodied male undergraduates at the University of Illinois during World War II who participated in the mile run.
02

Describe the Population Distribution

The population distribution of the mile run times is normally distributed. It is characterized by a mean (\(\mu\)) of 7.11 minutes and a standard deviation (\(\sigma\)) of 0.74 minutes.
03

Clarify Sampling Distribution of \(\overline{x}\)

The sampling distribution of the sample mean, \(\overline{x}\), is also normally distributed according to the Central Limit Theorem. It has the same mean as the population mean, 7.11 minutes, but the standard deviation is different. For samples of size 100, the standard deviation (also called the standard error) is 0.074 minutes, calculated as \(\frac{\sigma}{\sqrt{n}} = \frac{0.74}{\sqrt{100}} = 0.074\).
04

Comparison Between Population and Sampling Distribution

The population distribution reflects the times of all individuals and has a larger spread (standard deviation of 0.74 minutes). In contrast, the sampling distribution of \(\overline{x}\) shows the distribution of average times from samples of size 100 and has a smaller spread (standard deviation of 0.074 minutes). This reflects that sample means vary less than individual observations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental concept in statistics. It states that when you take large enough random samples from a population, the distribution of their means tends to be normal, regardless of the population's original distribution.
The CLT is crucial because it allows statisticians to make inferences about population parameters even when the population distribution is not normal.
In this exercise, even though the population distribution of run times is already normal, we see the impact of the CLT when the sample means (\(\overline{x}\)) are considered.
  • The sample mean distribution remains normal, consistent with CLT predictions.
  • It has a mean equivalent to the population mean (\(\mu = 7.11\)).
  • The standard deviation, reduced to 0.074, shows less variability in sample means compared to individual data points.
This reduction in variability reflects how averages from multiple samples showcase less fluctuation, making it easier to predict outcomes.
Population Distribution
Understanding population distribution is key to grasping the nature of data from the population. A population distribution details how individual scores or pieces of data are distributed across the entire group.
In the given exercise, the population includes 12,000 male undergraduates, with their mile run times following a normal distribution, characterized by:
  • A mean (\(\mu\)) of 7.11 minutes.
  • A standard deviation (\(\sigma\)) of 0.74 minutes, indicating the spread of run times.
These metrics describe a bell-shaped curve that reflects most individuals running times close to the mean, with fewer and fewer individuals achieving times further from the average.
This normal distribution allows for meaningful interpretations using standard statistical rules, such as determining probabilities of run times within certain intervals.
Standard Error
The Standard Error (SE) is a statistical measure that helps understand the precision of a sample mean compared to the population mean. It is defined as the standard deviation of the sampling distribution.
In this context, when samples of size 100 from the population are considered, the standard error is calculated as:\[SE = \frac{\sigma}{\sqrt{n}}\]where \(\sigma = 0.74\) is the population standard deviation and \(n = 100\) is the sample size.
The calculation gives:\[SE = \frac{0.74}{\sqrt{100}} = 0.074\]This value indicates that the sample mean's variability is much smaller than the variability of individual observation times.
  • Lower SE implies greater precision and stability in sampling results.
  • It helps quantify the variability reduction from individual data points to sample averages.
In practice, the SE assists researchers in determining how accurately a sample mean reflects the population mean, making it a critical component of statistical analysis.

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Most popular questions from this chapter

For Exercises 1 to \(4,\) identify the population, the parameter, the sample, and the statistic in each setting. Stop smoking! A random sample of 1000 people who signed a card saying they intended to quit smoking were contacted nine months later. It turned out that 210\((21 \%)\) of the sampled individuals had not smoked over the past six months.

A newborn baby has extremely low birth weight \((\mathrm{ELBW})\) if it weighs less than 1000 grams. A study of the health of such children in later years examined a random sample of 219 children. Their mean weight at birth was \(\overline{x}=810\) grams. This sample mean is an unbiased estimator of the mean weight \(\mu\) in the population of all ELBW babies, which means that (a) in all possible samples of size 219 from this population, the mean of the values of \(\overline{x}\) will equal 810 . (b) in all possible samples of size 219 from this population, the mean of the values of \(\overline{x}\) will equal \(\mu .\) (c) as we take larger and larger samples from this population, \(\overline{x}\) will get closer and closer to \(\mu\) (d) in all possible samples of size 219 from this population, the values of \(\overline{x}\) will have a distribution that is close to Normal. (e) the person measuring the children's weights does so without any systematic error.

Multiple choice: Select the best answer for Exercises 43 to \(46,\) which refer to the following setting. The magazine Sports Illustrated asked a random sample of 750 Division I college athletes, "Do you believe performance- enhancing drugs are a problem in college sports?" Suppose that 30\(\%\) of all Division I athletes think that these drugs are a problem. Let \(\hat{p}\) be the sample proportion who say that these drugs are a problem. The sampling distribution of \(\hat{p}\) is approximately Normal because (a) there are at least 7570 Division I college athletes. (b) \(n p=225\) and \(n(1-p)=525\) (c) a random sample was chosen. (d) a large sample size like \(n=750\) guarantees it. (e) the sampling distribution of \(\hat{\rho}\) always has this shape.

A sample of teens A study of the health of teenagers plans to measure the blood cholesterol levels of an SRS of \(13-\) to 16 -year olds. The researchers will report the mean \(\overline{x}\) from their sample as an estimate of the mean cholesterol level \(\mu\) in this population. (a) Explain to someone who knows no statistics what it means to say that \(\overline{x}\) is an unbiased estimator of \(\mu\) (b) The sample result \(\overline{x}\) is an unbiased estimator of the population mean \(\mu\) no matter what size SRS the study chooses. Explain to someone who knows no statistics why a large random sample gives more trustworthy results than a small random sample.

Do you drink the cereal milk? AUSA Today Poll asked a random sample of 1012 U.S. adults what they do with the milk in the bowl after they have eaten the cereal. Of the respondents, 67\(\%\) said that they drink it. Suppose that 70\(\%\) of U.S. adults actually drink the cereal milk. Let \(\hat{p}\) be the proportion of people in the sample who drink the cereal milk. (a) What is the mean of the sampling distribution of \(\hat{p} ?\) Why? (b) Find the standard deviation of the sampling distribution of \(\hat{p} .\) Check to see if the 10\(\%\) condition is met. (c) Is the sampling distribution of \(\hat{p}\) approximately Normal? Check to see if the Normal condition is met. (d) Find the probability of obtaining a sample of 1012 adults in which 67\(\%\) or fewer say they drink the cereal milk. Do you have any doubts about the result of this poll?

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