/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Exercises 27 and 28 refer to the... [FREE SOLUTION] | 91Ó°ÊÓ

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Exercises 27 and 28 refer to the following setting. Choose an American household at random and let the random variable X be the number of cars (including SUVs and light trucks) they own. Here is the probability model if we ignore the few households that own more than 5 cars: Number of cars X: 012345 Probability: 0.09 0.36 0.35 0.13 0.05 0.02 A housing company builds houses with two-car garages. What percent of households have more cars than the garage can hold? (a) 13\(\%\) (b) 20\(\%\) (c) 45\(\%\) (d) 55\(\%\) (e) 80\(\%\)

Short Answer

Expert verified
20\% of households have more cars than the garage can hold.

Step by step solution

01

Identify Events

We need to determine the probability of households having more than 2 cars. This is represented by the events where the random variable \( X \) is greater than 2.
02

List Probabilities for Relevant Events

The relevant events are \( X = 3, 4, 5 \). The probabilities associated with these events are: \( P(X=3) = 0.13 \), \( P(X=4) = 0.05 \), and \( P(X=5) = 0.02 \).
03

Sum Probabilities

To find the probability that a household has more than 2 cars, we sum the probabilities of \( X = 3, 4, 5 \).\[P(X > 2) = P(X=3) + P(X=4) + P(X=5) = 0.13 + 0.05 + 0.02 = 0.20\]
04

Convert Probability to Percentage

Since probabilities are expressed as decimals, multiply the result by 100 to convert it to a percentage:\[0.20 \times 100\% = 20\%\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In the world of probability, a **random variable** is a critical concept that represents outcomes of a probabilistic event. In our example, we have the random variable \( X \), which stands for the number of cars a household owns. Random variables can be discrete or continuous. Here, \( X \) is a discrete random variable because it can only take certain values, specifically 0, 1, 2, 3, 4, or 5 cars.

Each of these values can be thought of as a possible outcome, and it carries a respective probability that indicates how likely it is to occur.
  • For instance, the probability of a household owning 0 cars is 0.09.
  • Similarly, owning 2 cars is more likely with a probability of 0.35.
This structured relationship between values and probabilities is where random variables come into play, serving as the foundation for constructing probability models and for further statistical analysis.
Probability Distribution
A **probability distribution** gives us a comprehensive outlook on all possible values of a random variable and their corresponding probabilities. In our case, the probability distribution for the number of cars per household is given by the probabilities associated with each value of \( X \).

By examining the distribution:
  • The highest probability, 0.36, occurs at \( X = 1 \), meaning 36% of households own one car.
  • The least frequent event, 0.02, is found at \( X = 5 \), indicating very few households own five cars.
This probability distribution helps us understand not just the likelihood of each outcome, but also the behavior of the overall population. For example, by summing probabilities for \( X = 3, 4, \) and 5, we interpreted that 20% of households have more cars than a two-car garage can accommodate, which aligns with real-world decisions such as designing garage space.
Statistical Analysis
**Statistical analysis** involves examining, modeling, and interpreting data using various mathematical approaches. When dealing with a problem concerning the distribution of cars among households, statistical analysis is useful in answering key questions, like our initial query about garage capacity.

Here, the analysis is simplified into a few key steps:
  • Identifying possible events (e.g., \( X > 2 \) means more than two cars).
  • Calculating relevant probabilities (the transition from probabilities of \( X = 3, 4, 5 \) to total \( P(X > 2) \)).
  • Converting the resulting probability into a percentage for greater understanding (20%).
This structured approach allows for decisions based on data and insights, such as predicting housing needs or making renovations to increase garage capacity. By leveraging probability models and conducting a thorough statistical analysis, we gain a clearer picture of the patterns within our data, informing practical, real-world choices.

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Most popular questions from this chapter

Random numbers Let Y be a number between 0 and 1 produced by a random number generator. Assuming that the random variable Y has a uniform distribution, find the following probabilities: (a) \(P(Y \leq 0.4)\) (b) \(P(Y < 0.4)\) (c) \(P(0.1 < Y \leq 0.15 \text { or } 0.77 \leq Y < 0.88)\)

Geometric or not? Determine whether each of the following scenarios describes a geometric setting. If so, define an appropriate geometric random variable. (a) Shuffle a standard deck of playing cards well. Then turn over one card at a time from the top of the deck until you get an ace. (b) Lawrence is learning to shoot a bow and arrow. On any shot, he has about a 10\(\%\) chance of hitting the bull's-eye. Lawrence's instructor makes him keep shooting until he gets a bull's-eye.

Spell-checking Spell-checking software catches "nonword errors," which result in a string of letters that is not a word, as when "the" is typed as "teh." When undergraduates are asked to write a 250 -word essay (without spell-checking), the number X of nonword errors has the following distribution: $$ \begin{array}{ccccc}{\text { Value of } X :} & {0} & {1} & {2} & {3} & {4} \\\ {\text { Probability: }} & {0.1} & {0.2} & {0.3} & {0.3} & {0.1} \\\ \hline\end{array} $$ (a) Write the event "at least one nonword error" in terms of \(X\) . What is the probability of this event? (b) Describe the event \(X \leq 2\) in words. What is its probability? What is the probability that \(X<2 ?\)

Toothpaste Ken is traveling for his business. He has a new 0.85 -ounce tube of toothpaste that's supposed to last him the whole trip. The amount of toothpaste Ken squeezes out of the tube each time he brushes varies according to a Normal distribution with mean 0.13 ounces and standard deviation 0.02 ounces. If Ken brushes his teeth six times during the trip, what's the probability that he'll use all the toothpaste in the tube? Follow the four- step process.

Skee Ball Ana is a dedicated Skee Ball player (see photo) who always rolls for the 50 -point slot. The probability distribution of Ana's score \(X\) on a single roll of the ball is shown below. You can check that \(\mu_{X}=23.8\) and \(\sigma_{X}=12.63\) . Score: 10 20 30 40 50 Probability: 0.32 0.27 0.19 0.15 0.07 (a) A player receives one ticket from the game for every 10 points scored. Make a graph of the probability distribution for the random variable \(T=\) number of tickets Ana gets on a randomly selected throw. Describe its shape. (b) Find and interpret \(\mu_{T}\) . (c) Compute and interpret \(\sigma_{\mathrm{T}}\) .

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