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The Price of Diamond Rings. Online advertisements contained pictures of diamond rings and listed their prices, diamond weights (in carats), and gold purity. Based on data for only the 18-carat gold ladies' rings in the advertisements, the least-squares regression line for predicting price (in dollars) from the weight of the diamond (in carats) is \(\frac{18}{18}\) $$ \text { price }=-6047.75+11975.14 \text { carats } $$ a. What does the slope of this line say about the relationship between price and number of carats? b. What is the predicted price when number of carats \(=0\) ? How would you interpret this price?

Short Answer

Expert verified
a. Each additional carat increases the price by $11,975.14. b. Predicted price is -$6,047.75, indicating an unrealistic result for 0 carats.

Step by step solution

01

Understand the Equation

The regression equation given is \( \text{price} = -6047.75 + 11975.14 \times \text{carats} \). In this equation, the constant -6047.75 is the y-intercept, and the coefficient 11975.14 is the slope.
02

Analyze the Slope

The slope \( 11975.14 \) indicates that for each additional carat, the price of the diamond ring increases by $11,975.14. This means there is a positive relationship between the weight of the diamond and its price.
03

Evaluate the Intercept

Substituting 0 for the carats in the equation, we calculate the price as \( -6047.75 + 11975.14 \times 0 = -6047.75 \). The intercept represents the price when there are 0 carats of diamond, which practically doesn't happen as it implies the price of a ring with no diamond would be negative. This is not realistic but suggests that small-sized diamonds or the setting itself does not cover the base price.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least-Squares Regression Line
Regression analysis is a statistical method used to understand the relationship between variables. A useful tool in this analysis is the least-squares regression line. This line is the one that minimizes the sum of the squares of the vertical distances of the points from the line itself. It provides a mathematical formula, in the form of an equation, that can be used to predict the value of a dependent variable based on the value of an independent variable.

In our example, the equation \[ ext{price} = -6047.75 + 11975.14 imes ext{carats} \] represents the least-squares regression line. It is used to predict the price of diamond rings based on the weight of the diamonds. The term "least-squares" ensures that this prediction line is as close as possible to the actual data points, minimizing prediction errors.
Slope Interpretation
The slope of a regression line is crucial for understanding how changes in the independent variable affect the dependent variable. In our regression equation, the slope is 11975.14. This figure denotes how much the price of a diamond ring is expected to increase with each additional carat of diamond weight.

To break it down:
  • A positive slope, like in this example, implies that there is a direct relationship between the two variables. As the carat weight increases, so does the price.
  • The larger the absolute value of the slope, the steeper the line and the more significant the effect of changing one variable on the other.
Understanding the slope helps predict how much one can expect the price to change as the diamond weight changes.
Y-Intercept
The y-intercept in a regression equation has an important but sometimes less intuitive role. It is the point where the line crosses the y-axis, indicating the predicted value of the dependent variable when the independent variable is zero. In our equation, the y-intercept is \(-6047.75\).

This means that if the weight of the diamond were zero carats, the price prediction would be -$6047.75. While this doesn't make practical sense—since a diamond can't have zero weight—it serves a critical purpose in the equation. This negative value suggests that there is a baseline cost for smaller diamonds or just for the ring's setting. It's a mathematical artifact, reminding us to consider the range of realistic data inputs when interpreting regression outcomes.
Predicting Outcomes
One of the key applications of a regression line is predicting future values. With the regression equation, you can estimate the price of a diamond ring based on its carat weight. For example, by plugging in the carat size into the equation, you can get a price prediction.

Prediction can be straightforward:
  • Insert the desired carat weight into the equation.
  • Solve for the price, providing you with an estimated value for the ring.
This estimation can help consumers anticipate costs and sellers price their products. However, it's essential to keep in mind that predictions only apply accurately within the scope of the data used to form them. Predictions outside of this range must be approached with caution as they might not be as reliable.

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